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Allushta [10]
3 years ago
15

11. An airline charges $20 to check a piece of luggage up to 23 kilograms. For excess weight, it charges $5 more per kilogram. T

he airline rounds up to the next whole kilogram (a piece of luggage weighing 24.1 kg would be charged as 25 kg). The airline doesn't accept luggage over 32 kg. Which of the graphs below represents this information as a function?

Mathematics
2 answers:
AVprozaik [17]3 years ago
5 0

Answer:

It's the third graph

Step-by-step explanation:

Aleonysh [2.5K]3 years ago
4 0

Answer:

I would say the second one

Step-by-step explanation:

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Find x if y=-3<br> 2x/y+6=-4
igomit [66]
The answer is x = 3.

4 0
3 years ago
A tank contains 60 kg of salt and 1000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain
MissTica

Answer:

(a) 60 kg; (b) 21.6 kg; (c) 0 kg/L

Step-by-step explanation:

(a) Initial amount of salt in tank

The tank initially contains 60 kg of salt.

(b) Amount of salt after 4.5 h

\text{Let A = mass of salt after t min}\\\text{and }r_{i} = \text{rate of salt coming into tank}\\\text{and }r_{0} =\text{rate of salt going out of tank}

(i) Set up an expression for the rate of change of salt concentration.

\dfrac{\text{d}A}{\text{d}t} = r_{i} - r_{o}\\\\\text{The fresh water is entering with no salt, so}\\ r_{i} = 0\\r_{o} = \dfrac{\text{3 L}}{\text{1 min}} \times \dfrac {A\text{ kg}}{\text{1000 L}} =\dfrac{3A}{1000}\text{ kg/min}\\\\\dfrac{\text{d}A}{\text{d}t} = -0.003A \text{ kg/min}

(ii) Integrate the expression

\dfrac{\text{d}A}{\text{d}t} = -0.003A\\\\\dfrac{\text{d}A}{A} = -0.003\text{d}t\\\\\int \dfrac{\text{d}A}{A} = -\int 0.003\text{d}t\\\\\ln A = -0.003t + C

(iii) Find the constant of integration

\ln A = -0.003t + C\\\text{At t = 0, A = 60 kg/1000 L = 0.060 kg/L} \\\ln (0.060) = -0.003\times0 + C\\C = \ln(0.060)

(iv) Solve for A as a function of time.

\text{The integrated rate expression is}\\\ln A = -0.003t +  \ln(0.060)\\\text{Solve for } A\\A = 0.060e^{-0.003t}

(v) Calculate the amount of salt after 4.5 h

a. Convert hours to minutes

\text{Time} = \text{4.5 h} \times \dfrac{\text{60 min}}{\text{1h}} = \text{270 min}

b.Calculate the concentration

A = 0.060e^{-0.003t} = 0.060e^{-0.003\times270} = 0.060e^{-0.81} = 0.060 \times 0.445 = \text{0.0267 kg/L}

c. Calculate the volume

The tank has been filling at 6 L/min and draining at 3 L/min, so it is filling at a net rate of 3 L/min.

The volume added in 4.5 h is  

\text{Volume added} = \text{270 min} \times \dfrac{\text{3 L}}{\text{1 min}} = \text{810 L}

Total volume in tank = 1000 L + 810 L = 1810 L

d. Calculate the mass of salt in the tank

\text{Mass of salt in tank } = \text{1810 L} \times \dfrac{\text{0.0267 kg}}{\text{1 L}} = \textbf{21.6 kg}

(c) Concentration at infinite time

\text{As t $\longrightarrow \, -\infty,\, e^{-\infty} \longrightarrow \, 0$, so A $\longrightarrow \, 0$.}

This makes sense, because the salt is continuously being flushed out by the fresh water coming in.

The graph below shows how the concentration of salt varies with time.

3 0
3 years ago
Which relation is a function
Alenkinab [10]

Answer:

Top left

Step-by-step explanation:


In order for it to be a function, it has to pass the vertical line test.  So draw a line down the middle of the graphs.  If it passes once, then it is a function, if it passes more than once it is not.

3 0
3 years ago
I need help with this and also the explanation plz
RoseWind [281]

Answer:

The correct answer is 0 or A

Step-by-step explanation:

2/0+2 + 1/5 = 6/0+5

2/2 + 1/5 = 6/5

1 + 1/5 = 6/5

5/5 + 1/5 = 6/5

6/5 = 6/5

7 0
3 years ago
The equation of line s is y=1/3x-3. The equation of line t is y=-x+5. the equations of line s and t form a system of equations.
BigorU [14]
Y=-x+5

-x+5=1/3x-3
-x+8=1/3x
8=4/3x
6=x

y=-6+5
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C.
6 0
3 years ago
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