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REY [17]
3 years ago
8

WHAT IS THE PERCENTS OF 13/50 , 3/5 3/20 5/8 45/90 7/5 19/25

Mathematics
1 answer:
WITCHER [35]3 years ago
6 0
To convert a fraction to a percent, simply divide the numerator by the denominator and multiply the quotient (the result) by 100. 

1. \frac{13}{50}
Divide 13 by 50 to receive the quotient
13÷50=0.26
Multiply the quotient by 100 or simply move the decimal two places to the right. 
0.26×100=26
Add the "percent" symbol to your answer. (%)
As a result, the percent form of \frac{13}{50} is 26%

Similarly, all the fractions will follow the same procedure, in order for them to be converted to a percent. Simply add the percent symbol (%) after the result. 

2. \frac{3}{5} = 0.6 = 60%
3. \frac{3}{20} = 0.15 = 15%
4. \frac{5}{8} = 0.625 = 62.5%
5. \frac{45}{90} = 0.5 = 50%
6. \frac{7}{5} = 1.4 = 140%
7. \frac{19}{25} = 0.76 = 76%

Percent means "out of 100" or "parts per 100". For cases where the numerator is larger than the denominator (improper fraction), such as 7/5, the result will be larger than 100% as well, as the total number of parts exceeds the parts available. 




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Can you do 2 and 3 please and tell me how you got your answer?
alexandr402 [8]

Answer:

2. Sorry, I don't how to put that into words, because i'm trying to use calculators, then figure out how they got their answer.

3. C

Step-by-step explanation:

2. ^

3. to get the difference between two numbers, (100 and 50, for example,) you must just simply have them minus each other, like simple math. 100 - 50 = 50.

So your difference between the number 100, and the number 50, are 50.

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Pic attached for further detail
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Step-by-step explanation:

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6 0
3 years ago
Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod
goblinko [34]

(2+3)^{-1}\equiv5^{-1}\pmod7 is the number <em>L</em> such that

5L\equiv1\pmod7

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

2a\equiv1\pmod7\implies a\equiv4\pmod7

since 2*4 = 8, whose residue is 1 mod 7;

3b\equiv1\pmod7\implies b\equiv5\pmod7

which we got for free by finding the inverse of 5 earlier. So

2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7

and so <em>R</em> = 2.

Then <em>L</em> - <em>R</em> = 1.

6 0
3 years ago
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