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3 years ago

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Jamie Earns 10% commission on her sales after she has sold a minimum of $2000 each month for the lippy cosmetics company, last m

onth her sales totalled $2750.

1 answer:

Licemer1 [7]3 years ago

7 0

I'm sorry but I do not understand your question. It is not specified what you are looking for.

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How much times can 6 go into 48

DENIUS [597]

6 can go into 48 8 times. How I figured out?
Start multiplying from a small number like
6×6= 36
6×7=42
6×8= 48
until you see your number 48, or a number that is lower that 48, but can not go any higher than 48.

6 0

3 years ago

Find the volume of the shaded figure by subtracting the smaller volume from the larger

alekssr [168]

Answer:

a. $9a^3 - 9ab^2$

b. $9a(a^2 - b^2)$

Step-by-step explanation:

a.

$Volume = l*w*h$

$Volume_{smaller} = l*w*h$

Where, $l = 9a, w = b, h = b$

$Volume_{smaller} = 9a*b*b = 9ab^2$

$Volume_{larger} = l*w*h$

Where, $l = 9a, w = a, h = a$

$Volume_{smaller} = 9a*a*a = 9a^3$

Volume of the shaded figure = $9a^3 - 9ab^2$

b. $9a^3 - 9ab^2$ expressed in factored form:

Look for the term that is common to 9a³ and 9ab², then take outside the parenthesis.

$9a^3 - 9ab^2 = 9a(a^2 - b^2)$

6 0

3 years ago

Pls help me this is 7th grade (ADVANCED)

aleksandrvk [35]

Answer:

it (6,18,23)

Step-by-step explanation:

3 0

3 years ago

Expand and simplify (x+3)(x-4)

Vinvika [58]

Answer:

the following term =

$x { }^{2} - x - 12$

Step-by-step explanation:

here's the explanation in attached image.

i hope it helped

4 0

3 years ago

Read 2 more answers

SAT scores are normally distributed with a mean of 1,500 and a standard deviation of 300. An administrator at a college is inter

Rama09 [41]

Answer:

The administrator should sample 968 students.

Step-by-step explanation:

We have to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.88}{2} = 0.06$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a p-value of $1 - 0.06 = 0.94$ , so Z = 1.555.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation of 300.

This means that $n = 300$

If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?

This is n for which M = 15. So

$M = z\frac{\sigma}{\sqrt{n}}$

$15 = 1.555\frac{300}{\sqrt{n}}$

$15\sqrt{n} = 300*1.555$

Dividing both sides by 15

$\sqrt{n} = 20*1.555$

$(\sqrt{n})^2 = (20*1.555)^2$

$n = 967.2$

Rounding up:

The administrator should sample 968 students.

5 0

3 years ago