2+_3/458 find the product
Answer:
A) 0
Step-by-step explanation:
When x is divided by 11, we have a quotient of y and a remainder of 3
x/11 = y + 3
x = 11y + 3 ........(1)
When x is divided by 19, we have a remainder of 3 also
x/19 = p + 3 (p = quotient)
x = 19p + 3 ..........(2)
Equate (1) and (2)
x = 11y + 3 = 19p + 3
11y + 3 = 19p + 3
11y = 19p + 3 -3
11y = 19p
Divide both sides by 11
11y/11 = 19p/11
y = 19p/11
y and p are integers. 19 is a prime number. P/11 is also an integer
y = 19(integer)
This implies that y is a multiple of 19. When divided by 19, there is no remainder. The remainder is 0
There is no solution since ln(0) is undefined
Answer:
b
Step-by-step explanation:
1 plus 2 equals three
Make the coefficient of y the same in both equations:
To do this, multiply equation one by 2, and equation two by 5 (this will make the coefficient 10 in both).
14x + 10y = 38
-35x - 10y = -80
Eliminate the y variable by adding the equations from each other
(14x + 10y = 38)
+ (-35x - 10y = -80)
= -21x + 0y = -42
We now have -21x = -42. The y variable has been eliminated.
Solve for x
-21x = -42
Divide both sides by -21 to get x on its own.
x = 2
Substitute x into the equation to find y.
7*2+5y=19
14+5y=19
Subtract 14 from both sides.
5y=19-14
5y=5
Divide by 5 on both sides to get y on its own.
y=5/5
y=1
The answer is (2,1)
