All categories

3 years ago

40 POINTS been stuck on this i'd mean alot for yall to help i'll mark brianliest

Mathematics

2 answers:

g100num [7]3 years ago

8 0

Answer:

For the first blank: 8

For the second blank: I think it's 913

Step-by-step explanation:

First blank: To find the area of a square do (Length * Width) For the roof do 15 * 25 to get 375. Then divide by 100 and you get 3.75 but round to 4

That's for 1 half of the roof so do cover the whole roof you need 8.

Digiron [165]3 years ago

4 0

Answer:

First blank 8 second blank 913

Step-by-step explanation:

Ive done the same question before

You might be interested in

How do I find the measure of the interior angle?

nataly862011 [7]

Answer:

see the explanation

Step-by-step explanation:

we know that

The sum of the interior angles in any polygon is given by the formula

$S=(n-2)180^o$

where

n is the number of sides of the polygon

step 1

Find the sum of the interior angles in the given polygon

we have

$n=5\ sides$

substitute

$S=(5-2)180^o=540^o$

step 2

Find the value of x

we know that

$-3x+125+(45-x)+(-x+90)+80=540$

solve for x

$-5x+340=540$

$-5x=200\\x=-40$

step 3

Find the measure of each interior angle

substitute the value of x

Angle A

$-3(-40)=120^o$

Angle B

$80^o$

Angle C

$-(-40)+90=130^o$

Angle D

$45-(-40)=85^o$

Angle E

$125^o$

3 0

3 years ago

Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini

Nat2105 [25]

By inspection, it's clear that the sequence must converge to $\dfrac32$ because

$\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32$

when $n$ is arbitrarily large.

Now, for the limit as $n\to\infty$ to be equal to $\dfrac32$ is to say that for any $\varepsilon>0$ , there exists some $N$ such that whenever $n>N$ , it follows that

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|$

From this inequality, we get

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}$
$\implies|2n-1|>\dfrac5{2\varepsilon}$
$\implies2n-1\dfrac5{2\varepsilon}$
$\implies n\dfrac12+\dfrac5{4\varepsilon}$

As we're considering $n\to\infty$ , we can omit the first inequality.

We can then see that choosing $N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil$ will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that $N\in\mathbb N$ .

6 0

3 years ago

X^2+15^2=21^2<br> Help me please how do I figure out X after getting the totals of b and c?

MakcuM [25]

Answer:

the x would equal

$x=-6\sqrt{6} \\and\\x=6\sqrt{6}$

Step-by-step explanation:

4 0

2 years ago

Select the expression that is equivalent to the given polynomial.

lesantik [10]

Observe that $16r^4$ is the square of $4r^2$ , and 625 is the square of 25.

So, your expression is a difference of squares, and as such we can rewrite it as

$16r^4-625=(4r^2+25)(4r^2-25)$

Now again, $4r^2$ is the square of $2r$ , and 25 is the square of 5. So, we have a sum and a difference of squares.

But if we think of 25 as $-(5i)^2$ , we have again the difference of two squares, so we have

$4r^2+25=(2r+5i)(2r-5i)$

$4r^2-25=(2r+5)(2r-5)$

6 0

2 years ago

Help With Number 8 Please?

Radda [10]

The answer is about 8.14 years :)

Because, ↓

Unit Rate = $\frac{I}{1300 * 0.0425 }$ which is equal to → $\frac{450}{1300 * . 0425}$

and that's how I found out that my answer is 8.14 years

6 0

3 years ago

Read 2 more answers