Answer:
Towards this goal, this project aims to develop a statistical measure of the uncertainty of the decisions made on the friction ridge evidence (i.e., evidential value of fingerprint comparison), which ultimately can be referred to as a scientific basis of the identification decisions made in friction ridge analysis.
Explanation:
Answer:
Conduction, Convection and Radiation
Explanation:
Answer:
5010J
Explanation:
The following data were obtained from the question:
Mass (m) = 15g
Heat of fusion (ΔHf) = 334J/g
Heat required (Q) =..?
The heat energy required to melt the ice can be obtained as follow:
Q = m·ΔHf
Q = 15 x 334
Q = 5010J
Therefore, the heat energy required to melt the ice is 5010J.
Answer:
b. The final state of the substance is a gas.
d. The sample is initially a liquid. One or more phase changes will occur.
Explanation:
Methane has the following properties:
- Normal melting point: 90.7 K
- Normal boiling point: 111.65 K
*"Normal" refers to normal pressure (1 atm).
According to this, we can affirm:
- Below 90.7 K, methane is solid.
- Between 90.7 K and 111.65 K, methane is liquid.
- Above 111.65 K, methane is gas.
<em>A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158 K. Which of the following are true? Choose all that apply.</em>
<em>a. The liquid initially present will solidify.</em> FALSE. The liquid will vaporize.
<em>b. The final state of the substance is a gas.</em> TRUE.
<em>c. The sample is initially a solid.</em> FALSE. The sample is initially a liquid.
<em>d. The sample is initially a liquid. One or more phase changes will occur. </em>TRUE.
Answer : The volume of 4.9 M 
stock solution used to prepare the solution is, 12.24 ml
Solution : Given,
Molarity of aqueous solution = 1.20 M = 1.20 mole/L
Volume of aqueous solution = 50.0 ml = 0.05 L
(1 L = 1000 ml)
Molarity of stock solution = 4.9 M = 4.9 mole/L
Formula used :
where,
= Molarity of aqueous solution
= Molarity of stock solution
= Volume of aqueous solution
= Volume of stock solution
Now put all the given values in this formula, we get the volume of stock solution.
By rearranging the term, we get
Therefore, the volume of 4.9 M stock solution used to prepare the solution is, 12.24 ml
