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ExtremeBDS [4]
3 years ago
8

The temperature in a town started out at 55 degrees. By the end of the day the temperature dropped to -6 degrees.

Chemistry
1 answer:
garik1379 [7]3 years ago
4 0

Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

Start temperature = 55°Centigrade. (Initial temperature)

End of the Day      = -6°Centigrade. (Final temperature)

To Find:

How far did the temperature drop?

Solution:

We will have,

\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}

Substituting the above values in it we get

\textrm{Temperature drop}=-6-55\\\\\therefore \textrm{Temperature drop}=-61\° centigrade

Therefore the temperature drop is -61°Centigrade.

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Suppose a 250. mL flask is filled with 0.30 mol of N_2 and 0.70 mol of NO. The following reaction becomes possible:N_2(g) +O2 →
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Answer:

0.4 M

Explanation:

Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.

Because there's no O₂ in the beginning, the NO will decompose:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.30 0 0.70 Initial

+x +x -2x Reacts (the stoichiometry is 1:1:2)

0.30+x x 0.70-2x Equilibrium

The equilibrium concentrations are the number of moles divided by the volume (0.250 L):

[N₂] = (0.30 + x)/0.250

[O₂] = x/0.25

[NO] = (0.70 - 2x)/0.250

K = [NO]²/([N₂]*[O₂])

K = \frac{(\frac{0.70 -2x}{0.250})^2 }{\frac{0.30+x}{0.250}*\frac{x}{0.250} }

7.70 = (0.70-2x)²/[(0.30+x)*x]

7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)

4x² - 2.80x + 0.49 = 2.31x + 7.70x²

3.7x² + 5.11x - 0.49 = 0

Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70

x = 0.09 mol

Thus,

[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M

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Notice what happens to the numbers of protons, neutrons, and electrons when you
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Answer:

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What does the name 2–butene tell you about this hydrocarbon's molecular structure?
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The suffix -ene tells that there is a double bond present in the molecule, and the 2 tells where in the molecule the bond is located. The molecule looks like this:


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3 years ago
According to Boyle's law, what would happen to the pressure of a gas if the temperature were tripled as the number of moles and
raketka [301]

According to Boyle's law, if the temperature were tripled as the number of moles and the volume were held constant, the pressure would triple (option C).

<h3>What is Boyle's law?</h3>

Boyle's law is the observation that the pressure of an ideal gas is inversely proportional to its volume at constant temperature.

However, when the temperature of a gas is increased, the pressure of the gas also increases provided the volume is constant.

According to this question, the temperature of a gas tripled as the number of moles and the volume were held constant.

Therefore, according to Boyle's law, if the temperature were tripled as the number of moles and the volume were held constant, the pressure would triple.

Learn more about Boyle's law at: brainly.com/question/1437490

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1 year ago
Which statement best describes the motion of
Veseljchak [2.6K]

The dye molecules  move in a directed way from high to low  concentration

Explanation:

The statement that best describes the motion of dye molecule in water is directed from a region of high to low concentration. The motion of the particles of the dye in water is described as diffusion:

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Learn more:

diffusion brainly.com/question/6873289

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