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ExtremeBDS [4]
4 years ago
8

The temperature in a town started out at 55 degrees. By the end of the day the temperature dropped to -6 degrees.

Chemistry
1 answer:
garik1379 [7]4 years ago
4 0

Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

Start temperature = 55°Centigrade. (Initial temperature)

End of the Day      = -6°Centigrade. (Final temperature)

To Find:

How far did the temperature drop?

Solution:

We will have,

\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}

Substituting the above values in it we get

\textrm{Temperature drop}=-6-55\\\\\therefore \textrm{Temperature drop}=-61\° centigrade

Therefore the temperature drop is -61°Centigrade.

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Arisa [49]

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Explanation:

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6. H₂ + Cl₂ --------> HCl

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7. Cs₂O  -------->  Cs + O₂

Balanced equation

                2 Cs₂O  -------->  4 Cs + O₂

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8. H₂O  -------->  H₂ + O₂

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                 2 KI  -------->  2K + I₂

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                 2 NaCl  -------->  2 Na + Cl₂

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7 0
4 years ago
What are the factors that affect the rate of dissolution?
Liula [17]

Option (C) is the correct answer.

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Dissolution also depends upon the temperature, in warm solvent, solute dissolves readily whereas in cool solvent, solute dissolves slowly as particles have more movement energy.

Greater the surface area, there will be more contact between the solute particles and solvent particles which increases the rate of dissolving. Smaller the surface are, there will be less contact between the particles which decreases the rate of dissolving. For example: granulated sugar dissolves more readily due to larger surface area and one ice cube dissolves slowly due to smaller surface area.

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4 0
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4 years ago
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Korolek [52]

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6 0
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Read 2 more answers
1. Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liters of
Vika [28.1K]
<h3>  Question  1</h3>

 The number  of liter   of  hydrogen gas  that are formed   at STP is  

15.344 L

<u><em>  calculation</em></u>

<em>2 Na   +2 H₂O →  2NaOH  +H₂</em>

 calculate  the  moles of   Na

moles  =mass/molar mass

from periodic table the molar mass of Na =  23 g/mol

moles = 31.5 g /23 g /mol  = 1.37  moles


From  equation above the   mole   ratio  of  Na: H2   is  2:1  

therefore the  moles of H2  =1.37 x1/2 =0.685  moles


At  STP  1  moles  of a gas  = 22.4 L

              0.685   moles  =  ?  L

by cross multiplication

=[ (0.685  moles  x 22.4 L) /  1  mole  =15.344 L



<h3> Question 2</h3>

The  percent   yield       = 84.77%

<u><em>calculation</em></u>

4 Na + O₂   →   2 Na₂O

%yield  =actual yield / theoretical  yield  x 100

Actual  yield=  61.8 g

 <em>The theoretical  yield  is calculated as  below</em>

Step  1:  find the  moles  of Na

     moles =  mass /molar mass

 from periodic table the  molar mass  of Na = 23 g/mol

moles = 54.1 g /23 g/mol =2.352  moles

Step 2: use the  mole ratio to determine  the  moles  of Na₂O

 Na:Na₂O  is  4: 2  therefore the moles of Na₂O = 2.352  x 2/4 =1.176 moles

Step 3:   find  the theoretical mass  of Na₂O

mass =  moles  x  molar  mass

The molar mass  of Na₂O =  [(23 x 2 ) + 16]  =62 g/mol

mass  = 1.176 moles   x 62 g/mol = 72.9  g


%   yield   is therefore  = 61.8 g /72.9 x 100  = 84.77%



8 0
3 years ago
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