1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
crimeas [40]
2 years ago
5

A region c B region d C region a D region b

Mathematics
1 answer:
anyanavicka [17]2 years ago
3 0

Answer:

Region C

Step-by-step explanation:

y ≤ ¼ x + 3 maps the areas C and D including the common boundary line

y ≥ -x + 5 maps the areas B and C including the common boundary line

The common area mapped is C plus its boundaries

You might be interested in
What is an expression for 43 more than t
musickatia [10]
43 more than t

t + 43
7 0
3 years ago
Read 2 more answers
A random sample of 42 college graduates who worked during their program revealed that a student spent an average 5.5 years on th
Neko [114]

Answer:

5.5-2.701\frac{1.1}{\sqrt{42}}=5.04    

5.5+2.701\frac{1.1}{\sqrt{42}}=5.96    

So on this case the 99% confidence interval would be given by (5.04;5.96)

And the best option would be:

a. 5.04 and 5.96

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=5.5 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=1.1 represent the sample standard deviation

n=42 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=42-1=41

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,41)".And we see that t_{\alpha/2}=2.701

Now we have everything in order to replace into formula (1):

5.5-2.701\frac{1.1}{\sqrt{42}}=5.04    

5.5+2.701\frac{1.1}{\sqrt{42}}=5.96    

So on this case the 99% confidence interval would be given by (5.04;5.96)

And the best option would be:

a. 5.04 and 5.96

3 0
3 years ago
You can do one-half of a job in an hour. Your friend can do one-third of the same job in an hour. How long will it take to do th
Mariana [72]

You do:  1/2  job/hr

Your friend does:  1/3  job/hr

Together:       (1/2 + 1/3)  job / hr

                   = (3/6 + 2/6)  job/hr

                   =    5/6          job/hr .

Since you do  5/6 job/hr, the corresponding
inverse unit rate is 
                                 6/5  hr/job

                              = 1 and 1/5 hr/job

                              =  1.2 hours/job

                              = 1 hour 12 minutes  per job.

5 0
3 years ago
Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +
slava [35]
\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx

Taking x=7\tan\theta gives \mathrm dx=7\sec^2\theta\,\mathrm d\theta, so that the integral becomes

\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta
=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta
=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta
=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta
=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta

When \sec\theta>0, we have

=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta
=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta

and from here we can substitute u=\tan\theta to proceed from here.

Quick note: When we set x=7\tan\theta, we are implicitly enforcing -\dfrac\pi2 just so that the substitution can be undone later via \theta=\tan^{-1}\dfrac x7. But note that over this domain, we automatically guarantee that \sec\theta>0, so the absolute value bars can be dropped immediately.
6 0
3 years ago
Find x in this picture pls
blondinia [14]

Answer:

X=62

Step-by-step explanation:

solve half of it like 90 degrees +22 degrees. then minus from 180 degrees

3 0
3 years ago
Read 2 more answers
Other questions:
  • What type of polygon is formed by the points (5,3), (3,-4), and (8,-4)
    7·1 answer
  • Solve 2x^2+4x=6 by factoring
    13·1 answer
  • Help on Algebra work, please.
    13·1 answer
  • How many coefficients are in the expression 1/3y^2 - 18y + 9- 2y^-2
    15·1 answer
  • How often should you study
    14·1 answer
  • The perimeter of a rectangle is 24cm. If the length is 7cm, find the width.
    5·2 answers
  • How do I get m+1=m+ to have 1 solution pick 1 out of these numbers 3, -4, 2, 3m
    7·1 answer
  • Three more than twice a number b is equal to 13
    15·1 answer
  • The Smith family goes out for lunch, and the price of the meal is $45.The sales tax on the meal is 6%, and the family also leave
    6·1 answer
  • according to chebyshev's theorem, what perpent of the observatioons lie within plus and minus 2.5 standard deviations of the mea
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!