Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks. Two students in t
1 answer:
Answer:
The system of equation used to find the Total number of flash cards made are .
In <u>5 minutes</u>, each student will have <u>30</u> flash cards.
Step-by-step explanation:
Given:
Number of flash cards already made by Tristan = 5
Number of flash card Tristan makes in 1 min = 5
Number of flash card Josh makes in 1 min = 6
We need to find the How long will Josh have same number of flashcards.
Also We need to find how many flashcards will each student have at that point.
Solution:
Let the number of minutes be.
Now we can say that;
Total number of flash cards made by Tristan is equal to Number of flash cards already made by Tristan plus Number of flash card Tristan makes in 1 min multiplied by number of minutes.
framing in equation form we get;
Total number of flash cards made by Tristan =
Also We can say that;
Total number of flash cards made by Josh is equal Number of flash card Josh makes in 1 min multiplied by number of minutes.
framing in equation form we get;
Total number of flash cards made by Josh =
Hence the system of equation used to find the Total number of flash cards made are .
Now to find the number of minutes when both would have same number of flash cards we will make both the equation equal.
so we get;
On solving we get;
Combining like terms we get;
Hence It would take 5 minutes when both will have same number of flash cards.
To find the number of flash cards each would had at that time we will substitute value of in the system of equations.
so we get;
number of flash cards made by Tristan =
number of flash cards made by Josh =
Hence In <u>5 minutes</u>, each student will have <u>30</u> flash cards.
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then csc(</span>θ) = 257, but csc(θ) =
= 257
==> sin(<span>θ) =
it is positive, so now we can determine that is in Quadrant 2
sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj:
cosθ =
tanθ =
cos<span>θ = </span>
then csc(</span>θ) = 257, but csc(θ) =
==> sin(<span>θ) =
it is positive, so now we can determine that is in Quadrant 2
sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj:
cosθ =
tanθ =
cos<span>θ = </span>