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crimeas [40]
3 years ago
9

What is the arc measure for (BC)

Mathematics
1 answer:
AlekseyPX3 years ago
5 0

Answer:

92°

Step-by-step explanation:

The sum of interior angles in a triangle is 180°

<D+<B<C = 180°

59° + 75 + < B = 180°

134° + <B = 180°

<B = 46°

The measure of arc BC is twice of angle B so 46 × 2 = 92

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What polygon is shown below ?
Verizon [17]

Answer:Rhombus

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
For Problems 1-3, use the grid to the right.
alex41 [277]

Answer:

1. -5

2. -24

3. 0

Step-by-step explanation:

Sum means addition.

Product means multiplication.

A negative times a negative will give you a positive.

Anything times zero is zero.

1. -2 + 5 + (-8) = -5

2. -1 * -4 * -6 = -24

3. 10 * 0 *-9 = 0

8 0
3 years ago
FAST PLEASE HELP MEEE: At a certain high school, 35 students play only stringed instruments, 10 students play only brass instrum
lys-0071 [83]

Answer:

35=10+5+5+p

35=20+p

35-20=p

p=15

6 0
3 years ago
Based on sample results, a 90% confidence interval for the mean servings of fruit per day consumed by grade school children is (
Artemon [7]

Answer: 1.12

Step-by-step explanation:

The confidence interval for the mean \mu and margin of error E is given by :-

(\mu-E,\ \mu+E)                                             --------------(1)

The given confidence interval : (0.21, 2.45)              -------------(2)

From (1) and (2), we  have

\mu-E=0.21-------(3)\\\\\mu+E=2.45--------(4)

Subtract equation (3) from (4), we get

2E=2.45-0.21\\\\\Rightarrow\ 2E=2.24\\\\\Rightarrow\ E=\dfrac{2.24}{2}=1.12

Hence, the margin of error is 1.12 .

5 0
3 years ago
1. A MAP SCALE READS 1CM:5KM. IF A DISTANCE ON THE MAP MEASURES 7CM, THE ACTUAL DISTANCE WILL BE?. 2. A SCHOOL DINING HALL IS 35
Agata [3.3K]

Answer:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. 42^\circ

5. 16.73 m

Step-by-step explanation:

Solution 1.

Reading of map scale = 1cm:5km

i.e. 1 cm is equivalent to 5 km

Measurement of map  = 7 cm

Actual distance = Measurement of map \times 5

Actual distance = 7 \times 5 = <em>35 km</em>

-------------------

Solution 2.

Length of dining hall = 35 m

Measurement of map = 7 cm

Scale = Measurement of map : Length of dining hall (i.e. ratio)

Scale = 7 cm :35 m = <em>1 cm : 5 m</em>

-------------------

Solution 3.

Length of building = 30 m

Scale = 1 cm to 5m

5 m is equivalent to 1 cm on scale

1 m is equivalent to \frac{1}{5} cm on scale

30m is equivalent to \frac{1}{5} \times 30 = <em>6 cm</em> on scale

-------------------

Solution 4.

Angle of elevation of A from B = 42^\circ

Angle of depression of B from A = ?

Please refer to the image attached, we can clearly observe that both the angles (i.e. angle of elevation from A to B and angle of depression from B to A )will be equal.

Angle of depression of B from A = 42^\circ

-------------------

Solution 5.

Given that:

String length, or hypotenuse of triangle BC= 25 m

Angle of string with horizontal, \angle B  = 42^\circ

Please refer to the attached image for the clear understanding of the situation.

To find:

Height, AC = ?

We can use trigonometric identity:

sin\theta = \dfrac{Perpendicular}{Hypotenuse}

OR

sinB = \dfrac{AC}{BC}\\\Rightarrow sin42^\circ = \dfrac{AC}{25}\\\Rightarrow AC = 25 \times 0.67\\\Rightarrow AC = 16.73 m

============

So, the answers are:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. 42^\circ

5. 16.73 m

7 0
3 years ago
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