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suter [353]
3 years ago
8

Are hydroxides a type of oxide or are oxides and hydroxides two different things entirely?

Chemistry
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

Mark me as Brainilist please!!

Explanation:

Oxides and their hydroxide counterparts made possible the industrial innovations we live in. Indeed, steel is a member of this family. Earth's crust contains them in vast quantities, making them the second most common element.

On a molecular scale, you would find that each oxygen atom is coupled with metal or semimetal atoms that fill in the gaps between them in oxide minerals. Oxides are divided into two groups: simple oxides, with a single metal or semimetal added, and complex oxides, where several metals can be incorporated into the molecule's structure. Hydroxides, on the other hand, are composed of metal ions attached to a highly reactive hydroxide ion (OH). Minerals formed by hydroxide are softer and less dense than oxides and usually form at lower temperatures.

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How many moles of PCl5 can be produced from 28.0 g of P4 (and excess Cl2 )? Express your answer to three significant figures and
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0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us to use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.

<h3 /><h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

P₄ + 10 Cl₂ → 4PCl₅

1 mole of P₄ react with 10 mole of Cl₂ produces 4 moles of PCl₅.

According to Stoichiometry

\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}

n_{P_4} = \frac{\text{Given Mass}}{\text{Molar mass}}

      = \frac{28\ g}{124\ g/mol}

      = 0.22580645161 mol

Now put the value in above equation

\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}

\frac{0.22580645161}{1} = \frac{n_{PCl_5}}{4}

n_{PCl_5} = 0.903 mol

Thus from the above conclusion we can say that 0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).

Learn more about the Stoichiometry here: brainly.com/question/25829169

#SPJ4

5 0
2 years ago
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