Answer:
the first number is 5 the second number is 4
Step-by-step explanation:
first number = x
second number = y
X+2y=13 given this isolate x x = 13-2y
2x+y=14 substitute 13-2y for x
2(13-2y)+y=14
26-4y+y=14
-3y=-12
y=4 taking this number substitute into either equation above
x+2(4)=13
x+8=13
x=5
The answer to this equation is :-10x+38 because
-2x(x-3)+4(-2x+8)
(-2x+6)+(-8x+32)
(-2x+6)(-8x+32)
-2x+6-8x+32
-10x+38
Answer:
ill try! <3
Step-by-step explanation:
When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.
4/6
= 2/3
As we take total and divide by what we looking for
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