The answer is 5/4 in
The initial length:
1 ft = 12 in
8 ft = 8 * 12 in
= 96 in
The final length:
7 ft 10 3/4 in = 7 ft + 10 in + 3/4 in
= 7 * 12 in + 10 in + 3/4 in
= 84 in + 10 in + 3/4 in
= 94 in + 3/4 in
The cut if the initial length - final length:
96 in - 94 in - 3/4 in = 2 in - 3/4 in = 8/4 in - 3/4 in = 5/4 in
Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
Question:
A = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set A and one integer from set B. What is the probability that the sum of the two integers will equal 9?
A. 0.15
B. 0.20
C. 0.25
D. 0.30
E. 0.33
Answer:
Option B: 0.20 is the probability of the sum of the two integers.
Explanation:
The sample space for selecting 2 numbers is given by

We need to determine the probability that the sum of two integers will be equal to 9.
Hence, we need to add the two integers from the sets A and B such that their sum will be equal to 9.
Hence, the sets are 
Thus, the total number of sets whose sum is equal to 9 = 4
The probability that the sum of the two integers will equal 9 is given by



Thus, the probability that the sum of the two integers will equal 9 is 0.20
Hence, Option B is the correct answer.
Answer:
The system has one solution.
Both lines have the same y-intercept.
The solution is the intersection of the 2 lines.
Step-by-step explanation:
Lines are
slope = 0.5
y intercept(put x =0) =5
slope = 1
y intercept(put x =0 ) =5
Both are linear equation thus they have only one solution. Also two non parallel lines meet only at one point.
If you solve these linear equation coordinate of point of intersection of line on graph will come.
<h3>
Answer: x = 7 and y = 3</h3>
=====================================================
Explanation:
Apply the difference of squares rule
x² - 4y² = 13
x² - (2y)² = 13
(x - 2y)(x + 2y) = 13
Since x and y are positive integers, this means x-2y and x+2y are both integers as well.
The value 13 is prime. Its only factors are 1 and 13
Since the above equation shows 13 factoring into x-2y and x+2y, then we have two cases:
- A) x-2y = 1 and x+2y = 13
- B) x-2y = 13 and x+2y = 1
----------------
Let's consider case A
We have this system of equations

Add the equations straight down
- x+x becomes 2x
- -2y+2y becomes 0y = 0 which goes away
- 1+13 becomes 14
Therefore we have 2x = 14 solve to x = 7
From here, plug this into either equation to solve for y
x-2y = 1
7 - 2y = 1
-2y = 1-7
-2y = -6
y = -6/(-2)
y = 3
You should get the same result if you used x+2y = 13
----------------
Since we've found that x = 7 and y = 3, notice how case B is not possible
Example: x-2y = 13 becomes 7-2(3) = 13 which is false.
Also, x+2y = 1 would turn into 7+2(3) = 1 which is also false.
-----------------
Let's check those x and y values in the original equation
x² - 4y² = 13
7² - 4*(3)² = 13
49 - 4(9) = 13
49 - 36 = 13
13 = 13
The answer is confirmed.