Answer:
The concentration of the dilute sample will be 0.361 g/ml
Explanation:
If a solution is diluted into 1:10 ratio then the amount of solute of that solution will be decreased by 10 times.
The initial concentration of the stock solution was 3.61g/ml but when the solution is diluted in 1:10 ratio the solute concentration is also decreased by 10 times.SO at present the solute concentration becomes 3.61/10=0.361 g/ml.
After the first 2 min the 20 g are only 10g, (1 half-life)
after other 2 more min 5g (2 half-lives)
after other 2 more min 2.5 g (3 half-lives)
after 2 more 1.25 g (4 haf lifes)
Answer:
V₂ = 22.23 mL
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 25 mL
Initial pressure = 725 mmHg (725/760 =0.954 atm)
Initial temperature = 20 °C (20 +273 = 293 K)
Final pressure = standard = 1 atm
Final temperature = standard = 273.15 K
Final volume = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.954 atm × 25 mL × 273.15 K / 293 K × 1 atm
V₂ = 6514.63 mL . atm . K / 293 K . atm
V₂ = 22.23 mL
Answer:
Explanation:
Most copper is used in electrical equipment such as wiring and motors. This is because it conducts both heat and electricity very well, and can be drawn into wires. It also has uses in construction (for example roofing and plumbing), and industrial machinery (such as heat exchangers).
