Moles (mol) = mass (g) / molar mass (g/mol)
Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol
Hence moles of NaCl in the mixture is 0.372 mol.
Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.
mole % = (moles of desired substance / Total moles of the mixture) x 100%
Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
Total moles of mixture = moles of NaCl + KCl + LiCl
Mass of KCl = 3.74 g
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g / 74.6 g/mol = 0.050 mol
Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol
Total moles = 0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
= (0.372 mol / 0.652 mol) x 100%
= 57.06%
Hence, mixture has 57.06% of NaCl as the mole percentage.
Answer:
2.77g of
can be produced.
Explanation:
Use stoichiometry.
Balanced equation:
⇒ 

3 : 1 **
0.0623** :
= 0.0623


m= (0.020767)(133.34)
m= 2.77g
The addition of hydrogen carbonate to bromothymol blue turns the solution blue. Thus, option B is correct.
The balanced equation for the dissociation of bromothymol blue is:

The color of dissociated form is yellow and undissociated form is blue.
<h3>What is the final color of solution?</h3>
The addition of hydrogen carbonate results in the dissociated ions as:

The dissociation results in the increased hydrogen ion concentration. The undissociated form in the reaction mixture increases.
Thus, the color of the solution will turn blue. Hence, option B is correct.
Learn more about bromothymol blue, here:
brainly.com/question/24319054
The MC1R gene provides instructions for making a protein called the melanocortin 1 receptor. This receptor plays an important role in normal pigmentation. The receptor is primarily located on the surface of melanocytes, which are specialized cells that produce a pigment called melanin.