Answer : The formula of hexaaquamanganese(II)sulfate is ![[Mn(H_2O)_6]SO_4](https://tex.z-dn.net/?f=%5BMn%28H_2O%29_6%5DSO_4)
.
Explanation :
Rules for writing formulas of coordination complexes :
- Central metal is written first and then the ligands are written along with their prefixes.
- The anion ligands are written before the neutral ligands.
- If there are more than one anion ligands or neutral ligands then they are written in alphabetical order.
The given name of complex is, hexaaquamanganese(ii) sulfate.
In this, the central metal is manganese which is written as Mn and the ligand is water (which is a neutral ligand) is written as 
and an anion is sulfate which is written as 
.
Water is a neutral ligand and sulphate has a charge of -2. As the overall complex is neutral the metal bears a +2 charge which is represented in Roman numeral after the metal.
Therefore, the formula of hexaaquamanganese(II)sulfate is written as .
Answer:
The boiling point of the substances
Explanation:
Because Boiling point is an intensive property.
Answer:
2Fe(s) + 3O2(g) --------> 2FeO3(s)
Explanation:
According to the question, a battery was used to light the steel wool by bringing the terminals very close together. When the battery came into contact with the steel wool, current was sent out through the thin wire. This caused the iron to heat up quite well.
Iron reacts with oxygen under these conditions as follows;
2Fe(s) + 3O2(g) --------> 2FeO3(s)
This is the chemical reaction that occurs when the steel wool is set on fire.
Mass of Cl₂ : 164.01 g
<h3>Further explanation</h3>
A mole is a number of particles(atoms, molecules, ions) in a substance
This refers to the atomic total of the 12 gr C-12 which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles
Can be formulated :
N = n x No
N = number of particles
n = mol
No = 6.02.10²³ = Avogadro's number
mol Cl₂ :
mass Cl₂(MW=71 g/mol) :
Answer:
The answer to your question is 330 g of CHO
Explanation:
Data
Calories needed = 2200 kcal/day
CHO = 60%
Proteins = 15%
Fats = 25%
Grams of carbohydrates needed = ?
Process
1.- Calculate the number of calories in 60% of 2200 kcal
2200 kcal ---------------- 100%
x --------------- 60%
x = (60 x 2200) / 100
x = 1320 kcal
2.- Calculate the grams of CHO
1 g of CHO ---------------- 4 kcal
x ---------------- 1320 kcal
x = (1320 x 1) / 4
x = 1320/4
x = 330 g of CHO
