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3 years ago

15

How do you do metric Measures ?

1 answer:

Marina86 [1]3 years ago

3 0

What are u specifically asking

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Please answer this!!

balu736 [363]

Answer:

3,724 cubic inches

Step-by-step explanation:

All you have to do is multiply 19•14•14

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2 years ago

What is 2 to the 9th power

andrey2020 [161]

Answer:

it is 512

Step-by-step explanation:

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2 years ago

Cameron adds 4 new hats to his collection each year. He started with only 3. Find slope and the y intercept.

pantera1 [17]

The slope is 4. The y intercept is 3.

plz give brainliest if possible

3 0

3 years ago

In ΔQRS, s = 2.3 inches, ∠S=51° and ∠Q=44°. Find the area of ΔQRS, to the nearest 10th of an square inch.

postnew [5]

Answer:

Area of ΔQRS = 2.3 square inches

Step-by-step explanation:

From the given information,

<S + <Q + <R = $180^{o}$

51 + 44 + <R = $180^{o}$

95 + <R = $180^{o}$

<R = $180^{o}$ - 95

= $85^{o}$

<R = $85^{o}$

Applying the Sine rule, we have;

$\frac{q}{SinQ}$ = $\frac{r}{SinR}$ = $\frac{s}{SinS}$

Using $\frac{r}{SinR}$ = $\frac{s}{SinS}$

$\frac{r}{Sin 85}$ = $\frac{2.3}{Sin51}$

r = $\frac{2.3*Sin85}{sin51}$

= 2.9483

r = 2.9 inches

Also, $\frac{q}{SinQ}$ = $\frac{s}{SinS}$

$\frac{q}{Sin44}$ = $\frac{2.3}{Sin51}$

q = $\frac{2.3*Sin44}{Sin51}$

= 2.0559

q = 2.0 inches

From Herons formula,

Area of a triangle = $\sqrt{s(s-q)(s-r)(s-s)}$

s = $\frac{2.3 + 2.0 + 2.9}{2}$

= 3.6

Area of ΔQRS = $\sqrt{3.6(3.6-2.0(3.6-2.9)(3.6-2.3)}$

= 2.2895

Area of ΔQRS = 2.3 square inches

8 0

2 years ago

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Not sure what the answer is?

ladessa [460]

Answer:

I think you are correct

hope it is helpful to you ☺️☺️☺️☺️

6 0

3 years ago

Read 2 more answers