1. solve for X and y using both equations to find the point they cross in
−x − y = −5
y = x + 1
Plug in y into first equation
-x-(x+1)=-5
-x-x-1=-5
-2x-1=-5
+1 both sides
-2x=-4
÷-2 both sides
x=2 solve for y
y=2+1
y=3
(2,3)
2. you can set them equal to each other so 2x+4=3x+1
Answer:
2663 ft
Step-by-step explanation:
Using SOHCAHTOA:
Solve for x:
Answer:
The answer is below
Step-by-step explanation:
The question is not complete but I would show how this charges can be represented by an equation.
For health club A:
The graph (x, y) passes through the points (2, $136) and (4, $242). Let x represent the total months and y represent the total charges. The equation is given by:
For health club B:
The table (x, y) has the points (4, 173) and (6, 23y). Let x represent the total months and y represent the total costs. The equation is given by:
<span>Simplifying
3a2 + -2a + -1 = 0
Reorder the terms:
-1 + -2a + 3a2 = 0
Solving
-1 + -2a + 3a2 = 0
Solving for variable 'a'.
Factor a trinomial.
(-1 + -3a)(1 + -1a) = 0
Subproblem 1Set the factor '(-1 + -3a)' equal to zero and attempt to solve:
Simplifying
-1 + -3a = 0
Solving
-1 + -3a = 0
Move all terms containing a to the left, all other terms to the right.
Add '1' to each side of the equation.
-1 + 1 + -3a = 0 + 1
Combine like terms: -1 + 1 = 0
0 + -3a = 0 + 1
-3a = 0 + 1
Combine like terms: 0 + 1 = 1
-3a = 1
Divide each side by '-3'.
a = -0.3333333333
Simplifying
a = -0.3333333333
Subproblem 2Set the factor '(1 + -1a)' equal to zero and attempt to solve:
Simplifying
1 + -1a = 0
Solving
1 + -1a = 0
Move all terms containing a to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + -1 + -1a = 0 + -1
Combine like terms: 1 + -1 = 0
0 + -1a = 0 + -1
-1a = 0 + -1
Combine like terms: 0 + -1 = -1
-1a = -1
Divide each side by '-1'.
a = 1
Simplifying
a = 1Solutiona = {-0.3333333333, 1}</span>
Given coordinates of the triangle RST are R(2,1), S(2,-2) and T(-1,-1).
Center of center of dilation is (2,-2).
Because center of dilation is (2,-2) so the coordinates of dilated image S(2,-2) would stay same.
Now, we need to apply rule for dilation with the scale factor 5/3.
Each of R(2,1), and T(-1,-1) would be and R' and T' would be in ratio 5/3.
We will extend RS to 5 units and TS also 5 units.
The new resulting image would be dilated triangle by a scale factor 5/3.