Answers:
x = 4
EF = 14
CF = 7
EC = 7
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Work Shown:
C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent.
Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4
Now that we know that x = 4, we can use this to find EC and CF
Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7
Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
CF = 7
As expected, EC = CF (both are 7 units long).
By the segment addition postulate, we can say EC+CF = EF
EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14
C. For sure. Hope it helps
Answer:
x^2 + x + 2 = 0.
Step-by-step explanation:
The discriminant b^2 - 4ac is < 0 for complex roots.
So we can choose appropriate values for a, b and c.
Let b = 1, a = 1 and c = 2 so b^2 - 4ac = 1 - 4*1*2 = -7.
So our equation is:
x^2 + x + 2 = 0.
Answer:
−5x^10
Step-by-step explanation:
-(5x5x5)
−5x^5x^5
add the exponets and you should get
−5x^10
