line segment AB is perpendicular to line segment CD . How many 90° angles are formed by the intersection?

PLEASE HELP I will give five stars and a thanks and brainly

PilotLPTM [1.2K]

Answer:

We can divide an algebraic term by another algebraic term to get the quotient. The steps below show how the division is carried out.

We can multiply two algebraic terms to get a product, which is also an algebraic term.

Step-by-step explanation:

3 0

2 years ago

Image attached.help me plz

kirill [66]

Answer:

1st option

Step-by-step explanation:

For any input of value x, the output y is always 2. The equation would then be y = 2, which would have 0 slope.

8 0

3 years ago

Read 2 more answers

Some one can help me please

Ne4ueva [31]

Answer:

C

Step-by-step explanation:

Let's say Abudal's score = x.

We can do,

3x + x + x + 5 = 45

5x = 45

x = 8.

That means Abdul's scored 8 points, meaning Kendall scored 24,(8*3), and that Otis scored 13, since 8 + 5 = 13.

4 0

2 years ago

In Major League Baseball, the American League (AL) allows a designated hitter (DH) to bat in place of the pitcher, but in the Na

hammer [34]

Answer:

Step-by-step explanation:

From the given information:

Let:

$\mu_1$ represent the population mean no. for DH group.

$\mu_2$ represent the population mean no. for no DH group

$n_1$ represent the sample sizes of DH

$n_2$ represent the sample sizes of no DH

Sample size: $n_1 = n_2 = 20$

For both groups, the population standard deviation of runs scored = 2.54

i.e

$\sigma^2_1 = \sigma_2^2 = 2.54$

The null & alternative hypothesis;

$H_o : \mu_1 \le \mu_2 \\ \\ H_a: \mu_1 > \mu_2$

Level of significance:

The test statistics is:

$z = \dfrac{\bar x_1 - \bar x_2}{\sqrt{\dfrac{\sigma^2_1}{n_1} + \dfrac{\sigma_2^2}{n_2} }}$

where;

$\bar x_1$ = sample mean for DH group

$\implies \dfrac{1}{n_1} \sum \limit ^{n_1}_{i=1} x_1 \\ \\ = \dfrac{1}{20}(0+6+8+2+2+4+7+7+6+5+1+1+5+4+4+5+7+11+10+0) \\ \\ = \dfrac{92}{20}$

= 4.6

$\bar x_2$ = sample mean for no DH group

$\implies \dfrac{1}{n_2} \sum \limit ^{n_1}_{i=1} x_1 \\ \\ = \dfrac{1}{20}(3+6+2+4+0+5+7+6+1+8+12+4+6+3+4+0+5+2+1+4) \\ \\ = \dfrac{83}{20}$

= 4.15

Now:

$z = \dfrac{4.60- 4.15}{\sqrt{\dfrac{2.54^2}{20} + \dfrac{2.54^2}{20} }} \\ \\ = \dfrac{0.45}{\sqrt{0.32258 +0.32258 }} \\ \\ = \dfrac{0.45}{0.803219} \\ \\$

= 0.5602

Since the test is one-tailed by looking at that $H_a:$

The P-value = $P(Z > z)$

$\implies 1 - P(Z \le z) \\ \\ = 1 - P(Z \le 0.5602)$

Using Excel Function " =normdist(z)"; we have":

$= 1- 0.7123$

P-value = 0.2877

Decision rule: To reject $H_o$ , if $p-value < \alpha \ at \ 0.10$

Conclusion: SInce P = 0.2877 which is $> \ \alpha \ at \ 0.10.$

We fail to reject the $H_o$ and conclude that there is insufficient evidence to support the given claim that: $\text{more runs are scored in games for which DH is used.}$

8 0

2 years ago

Lily read 4 books in December and read 7 books in January. What percent did she increase the number of books she read?

OLEGan [10]

Answer: 175%

Step-by-step explanation:

7/4 x 100 = 1.75

5 0

2 years ago