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4 years ago

Which substances were ionic?

Chemistry

2 answers:

horsena [70]4 years ago

6 0

<h3>Sodium chloride and Sodium bicarbonate are ionic substances</h3><h3>Further explanation </h3>

Atoms have different stability. Unstable atomic atoms will try to form stable electron configurations like those of noble gases. Where noble gases have the number of outer electrons 2 or 8

The formation of electron configurations such as noble gases can be done by sharing electrons with covalent bonds or hand over electrons with ionic bonds

Generally, ionic bonds occur in metals and nonmetallic elements.

While covalent bonds occur because of the use of shared electrons. In general, this bond occurs between nonmetallic elements, which has the same electron attraction

Characteristics of ionic compounds include: solid / crystalline form, soluble in water, conduct electricity

Let see the answer choices

It is a covalent compound because part of the hydrocarbon, a liquid that forms a bond between elements C, H and O, and does not dissolve in water (floats on water)

Cornstarch

Obtained from corn which contains glucose which is a carbohydrate. It does not dissolve in water. Contains a bond between C, H and O. Includes covalent compounds

Sodium chloride
Sodium bicarbonate

Both are ionic compounds, soluble in water, in solid form

NaCl ⇒ Na⁺ + Cl⁻

NaHCO₃⇒ Na⁺ + HCO₃⁻

<h3>Learn more </h3>

ionic bonding

brainly.com/question/1603987

Type of atoms typically form covalent bonds

brainly.com/question/13648552

the ionic compound LiI

brainly.com/question/2732123#

Keywords : ionic, covalent, Oil ,Cornstarch ,Sodium chloride,Sodium bicarbonate

#LearnWithBrainly

Papessa [141]4 years ago

6 0

Answer:

In this case the answers are

sodium bicarbonate

Sodium chloride

Explanation:

Hello!

Let's solve this!

Ionic substances are substances that are soluble in water. In solution they are separated into positive inodes (cations) and negative inoes (anions).

In this case the answers are

sodium bicarbonate

NaHCO3 ---> Na + + HCO3-

sodium chloride

NaCl ---> Na + + Cl-

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A sample of gas occupies a volume of 50.0 milliliters in a cylinder with a movable piston. The pressure of the sample is 0.90 at

alina1380 [7]

P₁ = 0.90 atm

V₁ = 50.0 mL

T₁ = 298 K

P₂ = 1 atm

T₂ = 273 K

V₂ = P₁ x V₁ x T₂ / T₁ x P₂

V₂ = 0.90 x 50.0 x 273 / 298 x 1

V₂ = 12285 / 298

V₂ = 41 mL

Answer (1)

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7 0

3 years ago

A sample of gold (Au) has a mass of 35.12 g..

VMariaS [17]

A) Molar mass gold ( Au) = 196.96 g/mol

1 mole Au ----------- 196.96 g
? moles Au ---------- 35.12 g

35.12 x 1 / 196.96

= 0.178 moles of Au
_____________________________

b) 196.96 g --------------- 6.02x10²³ atoms
35.12 g ---------------- ( atoms ? )

35.12 x ( 6.02x10²³) / 196.96

2.114x10²⁵ / 196.96

= 1.07x10²³ atoms
_____________________________________________

7 0

3 years ago

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Does water diffuse faster in water or agar

ki77a [65]

Wait wait wait, did you mistype your question? Water and water would just mix together, agar is thicker than water.

5 0

4 years ago

A voltaic cell consists of a Zn>Zn2+ half-cell and a Ni>Ni2+ half-cell at 25 °C. The initial concentrations of Ni2+ and Zn

nlexa [21]

Answer :

(a) The initial cell potential is, 0.53 V

(b) The cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M is, 0.52 V

(c) The concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V are, 0.01 M and 1.59 M

Explanation :

The values of standard reduction electrode potential of the cell are:

$E^0_{[Ni^{2+}/Ni]}=-0.23V$

$E^0_{[Zn^{2+}/Zn]}=-0.76V$

From this we conclude that, the zinc (Zn) undergoes oxidation by loss of electrons and thus act as anode. Nickel (Ni) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : $Zn\rightarrow Zn^{2+}+2e^-$ $E^0_{[Zn^{2+}/Zn]}=-0.76V$

Reaction at cathode (reduction) : $Ni^{2+}+2e^-\rightarrow Ni$ $E^0_{[Ni^{2+}/Ni]}=-0.23V$

The balanced cell reaction will be,

$Zn(s)+Ni^{2+}(aq)\rightarrow Zn^{2+}(aq)+Ni(s)$

First we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=E^o_{[Ni^{2+}/Ni]}-E^o_{[Zn^{2+}/Zn]}$

$E^o=(-0.23V)-(-0.76V)=0.53V$

(a) Now we have to calculate the cell potential.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = emf of the cell = ?

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(0.100)}{(1.50)}$

$E_{cell}=0.49V$

(b) Now we have to calculate the cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M.

New concentration of $Ni^{2+}$ = 1.50 - x = 0.500

x = 1 M

New concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1 = 1.1 M

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(1.1)}{(0.500)}$

$E_{cell}=0.52V$

(c) Now we have to calculate the concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}+x]}{[Ni^{2+}-x]}$

Now put all the given values in the above equation, we get:

$0.45=0.53-\frac{0.0592}{2}\log \frac{(0.100+x)}{(1.50-x)}$

$x=1.49M$

The concentration of $Ni^{2+}$ = 1.50 - x = 1.50 - 1.49 = 0.01 M

The concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1.49 = 1.59 M

5 0

3 years ago

Which of the following gases will have the highest rate of effusion at a given temperature?

Nataliya [291]

Answer:

He.

Explanation:

Graham's law states that the effusion rate is inversely proportional to the molecular weight. It means that the gas with the lowest molecular weight will have the highest effusion rate.

The molecular weights of the given gases are:

Cl₂ = 70.9 g/mol.

He = 2.0 g/mol.

O₂ = 32.0 g/mol.

Ne = 20.17 g/mol.

<em>Since He has the smallest molecular mass, so it will have the highest rate of effusion.</em>

5 0

3 years ago

Read 2 more answers