True i really don’t feel like giving an explanation but trust me it’s trye
5A(oic)nehrddfbfbffbdgdgdv
<span>divide the 201g by the mol mass of the compound. Just add up the masses of the various element</span>
K5O2
convert grams to moles, divide both by the smallest mole mass, multiply that until hole.
30.5 g K ÷ 39.10 = .78 mol
6.24 g O ÷ 16 = .39 mol
.78 mol ÷ .39 mol = 2.5
.39 mol ÷ .39 mol = 1
2.5 x 2 = 5
1 x 2 = 2
K5O2
