<span>Atomic number and mass number for the carbon isotope with seven neutrons are:
Z,A = 6,13
There are 3 isotopes of carbon that are carbon 12, carbon 13 and carbon 14.
The carbon atom with seven neutron is carbon 13. Each carbon has 6 protons so its atomic number is 6 and when it has seven neutron then mass number will be (6 + 7) = 13
So, atomic number Z is 6 and mass number A is 13.</span>
Since the sample size is below 30, in this case we use
the t statistic. The formula for t score is:
t = (x – u) / (σ / sqrt n)
where,
x = the level l = unknown
u = sample mean = 120 mg / dl
σ = standard deviation = 20 mg / dl
n = sample size or number of results = 5
Using the standard distribution tables for t, we can find
the value of t given the probability (P = 0.15) and degrees of freedom (DOF).
t = 1.036
Going back to the
formula for t score:
1.036 = (x – 120)
/ (20 / sqrt 5)
x = 129.27 mg /
dl = l
The concentration of the solution is also known as Molarity (M). The formula for molarity is
M = mol / liters
We already have the liters, so we only need to find moles. We can find the number of moles by using the molar mass of NaCl and the given amount. That can be found using the elements' atomic weights given on the periodic table.
22.990 (mass of Na) + 35.453 (mass of Chlorine) = 58.443 g / mol
That's how many grams are in one mole of NaCl, but we only have 2.5 grams. So, let's divide and see how many moles we have.
2.5 / 58.443 = .042776 moles
Now we can plug our numbers into the formula.


M = .02138 mols/L
So, your concentration is about .02 mol/L.
Answer:
Please find the structure attached as an image
Explanation:
Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.
- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.
- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).
N.B: In the structure attached below, the counting is from the left to right (→).