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2 years ago

Organisms that depend on other organisms for food are consumers. Which consumer think is a herbivore (eats plants only)

Chemistry

2 answers:

podryga [215]2 years ago

6 0

Examples of herbivores are buffalo, elk, some bird species, mice, squirrels, rabbits, and many more.

ehidna [41]2 years ago

4 0

Answer:

cow

Explanation:

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A brick measures 25 cm by 12 cm by 13 cm. What is the volume of the brick in cm3? How many milliliters of water would this brick

hodyreva [135]

Volume is lxwxh so do 25x12x13

7 0

3 years ago

How much of strontium-90 will be left after 40 hours if you start with 960 grams and the half-life is 10 hours?

zmey [24]

Answer:

5 hours

Explanation:

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1 year ago

El compuesto es soluble en agua y conduce la eletricidad

salantis [7]

Answer:

creo que si

Explanation:

por que si vienes a ver has un experimento con agua y electricidad. por eso es que el compuesto es soluble en agua y conduce la electricidad

6 0

2 years ago

Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec

Svetach [21]

The overall reaction is given by:

$Br_{2}(g) + 2 NO(g) \rightarrow 2 NOBr(g)$

The fast step reaction is given as:

$NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})$

The slow step reaction is given as:

$NOBr_{2}(g) + NO(g) \rightarrow 2 NOBr(g)$ (slow step $k_{2}$ )

Now, the expression for the rate of reaction of fast reaction is:

$r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]$

The expression for the rate of reaction of slow reaction is:

$r_{2}=k_{2}[NOBr_{2}] [NO]$

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as $[NOBr_{2}]$ takes place in this reaction.

The expression of rate of formation is:

$\frac{d(NOBr)}{dt}=r_{2}$

= $k_{2}[NOBr_{2}][NO]$ (1)

Now, consider that the fast step is always is in equilibrium. Therefore, $r_{1}=0$

$k_{1}[NO][Br_{2}]= k_{-1}[NOBr_{2}]$

$[NOBr_{2}] = \frac{k_{1}}{k_{-1}}[NO][Br_{2}]$

Substitute the value of $[NOBr_{2}]$ in equation (1), we get:

$\frac{d(NOBr)}{dt}=k_{2}[NOBr_{2}][NO]$

= $k_{2} \frac{k_{1}}{k_{-1}}[NO][Br_{2}][NO]$

= $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$

Thus, rate law of formation of $NOBr$ in terms of reactants is given by $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$ .

4 0

2 years ago

Which describes a scenario in which the Doppler effect is occurring?

s2008m [1.1K]

The correct answer is option B, that is, the pitch changes from low to high.

The Doppler shift or the Doppler Effect refers to the variation in the wavelength or frequency of a wave in association with an observer who is traveling comparative to the source of the wave. A prime illustration of Doppler shift is the modification of the pitch heard when a vehicle sounding a horn comes towards and move away from an observer.

In comparison to the frequency emitted, the obtained frequency is greater at the time of approach, similar at the instant of passing by, and lower at the time of recession.

8 0

2 years ago

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