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ivann1987 [24]
4 years ago
11

Which of the following is a single replacement reaction?

Chemistry
2 answers:
vivado [14]4 years ago
7 0

Answer:

The correct answer is D) Fe + 3NaBr → FeBr3 + 3Na

Explanation:

IrinaK [193]4 years ago
6 0

Answer:

Fe + 3NaBr    →   FeBr₃ + 3Na

Explanation:

Single replacement:

It is the reaction in which one elements replace the other element in compound.

AB + C → AC + B

Chemical equation:

Fe + 3NaBr    →   FeBr₃ + 3Na

This chemical equation shows the single replacement reaction. Iron replace the sodium and react with bromine.

All other options are incorrect because,

Ca(OH)₂ + H₂SO₄      →     CaSO₄  + 2H₂O

It is double replacement reaction.

CH₄ + 2O₂     →     CO₂  + 2H₂O

This reaction equation shows combustion.

H₂O + CO₂  →    H₂CO₃

This is synthesis reaction.

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Group 1 elements have an average electronegativity of 0.84 (not including hydrogen). Group 17 elements have an average electrone
aivan3 [116]

We have that the Electronegative difference of 2.15 basically makes ionic bonds

Ionic bonds is to be formed

<h3>Bonding</h3>

Generally, the common electronegativity of the team 1 <u>factors </u>are 0.84 and the common <em>electronegativity </em>of the team 17 factors are 2.99.

Group 17 factors are an awful lot greater electronegative than Group 1 elements.

Group 17 consists of F, Cl, Br and I,Group 1 factor that is Na loses 1 electron from its outermost orbit and varieties Na+ cation.

Group 17 Element that is Cl accepts 1 electron in its outermost orbit and Creates Cl- anion. Now, Na+ cation and Cl- anion combines collectively by using ionic bonds.

Hence, the electronegative difference

(2.99-0.84)=2.15

Electronegative difference of 2.15 basically makes ionic bonds

For more information on Bonding visit

brainly.com/question/819068

3 0
3 years ago
Air enters a diffuser witha velocity of 400 m/s, a pressure of 1 bar and temperature of 25 C. It exits with a temperature of 100
ANEK [815]

Answer:

Exit velocity of air is 96.43 m/s.

Explanation:

Given that

V_1=400\ m/s

T_1=25C

T_2=100C

For air

C_p=1.005\ KJ/kg.K

Now from first law of thermodynamics for open system at steady state

h_1+\dfrac{V_1^2}{2000}+Q=h_2+\dfrac{V_2^2}{2000}+w

For diffuser

h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}

We know that

h=C_pT

h_1+\dfrac{V_1^2}{2}=h_2+\dfrac{V_2^2}{2000}

1.005\times 25+\dfrac{400^2}{2000}=1.005\times 100+\dfrac{V_2^2}{2}

V_2=96.43\ m/s

So the exit velocity of air is 96.43 m/s.

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