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Vera_Pavlovna [14]
4 years ago
12

In a randomly generated list of numbers from 0 to 4, the chance that each

Mathematics
1 answer:
Mamont248 [21]4 years ago
7 0

Answer: false

Step-by-step explanation:

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Find the measures of the interior angles of the triangle
Oksi-84 [34.3K]

Answer:

A = 75°

B = 90°

C = 15°

Step-by-step explanation:

The diagram tells us that C = 15°.

The diagram places a square in the angle of B, showing you the angle is a 90° right angle.

You can solve for A because all angles of a triangle must equal 180°. 180° - 90° (B) = 90°. 90° - 15° (C) = 75°, the measure of A.

6 0
3 years ago
Tasha believes that she can rewrite the differences 48-36 as a product of the GCF of the two numbers and another difference. Is
horrorfan [7]

Answer:

Tasha is correct

Step-by-step explanation:

7 0
3 years ago
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A bag has 3 red rocks, 4 green rocks, 3 blue rocks, 3 speckled rocks,
jolli1 [7]

Answer:

3/17 or 17.64%

Step-by-step explanation:

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3 years ago
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At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca
saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

P(A \cap B) = 0.11*0.75 = 0.0825

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0
3 years ago
Jonathan's parents told him that for every 5 hours of Academic Prep work he completes, he would be able to play 3 hours of video
Over [174]

Answer: Jonathan spends more time playing video games because 3/5 of the time he is playing video games, while Lucas is only playing thirty minutes out of sixty, which simplifies into 1/2. Jonathan plays 60% of the time and Lucas plays 50%.

Step-by-step explanation:

7 0
3 years ago
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