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tekilochka [14]
3 years ago
5

Which of the following is a arithmetic sequence?

Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Answer:

What are the options

Step-by-step explanation:

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Find the value of X in each of the given triangles.​
pychu [463]

Answer:

x = 24

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

  • All angles in a triangle add up to 180°

Step-by-step explanation:

<u>Step 1: Set Up Equation</u>

3x + 2x + 60° = 180°

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                    5x + 60 = 180
  2. Isolate <em>x </em>term:                              5x = 120
  3. Isolate <em>x</em>:                                       x = 24
8 0
3 years ago
132 books are printed in 2 hours, 264 books are printed in 4 hours, and 528 books in 8 hours, how many books are printed in 3 ho
maxonik [38]
So the unit rate is 66:1
then you do 66*3=198
198:3
then you do the same thing 66*7=462
462:7
lastly you do 66*15=990
990:15
3 0
3 years ago
Try to get to every number from 1 to 10 using four 4's and any number of arithmetic operations (+, −, ×, ÷). You may also you pa
stepan [7]

Answer:

Step-by-step explanation:

1. 4/4+4-4=1

2. 4/4+4/4=2

3. 4+4/4-4=3

4. 4 × (4 − 4) + 4=4

5. (4 × 4 + 4) / 4=5

6. 44 / 4 − 4=6

7. 4+4-4/4=7

8. 4+4+4-4=8

9. 4+4+4/9=9

10. 44 / 4.4=10

6 0
3 years ago
Read 2 more answers
Can someone help me with this?!
NNADVOKAT [17]

Answer:

\sqrt{0/9}

Step-by-step explanation:

Have a good day :)

4 0
3 years ago
TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN
borishaifa [10]

Answer:

<u>A. It would be needed 20 packets to transmit 30,000 bytes of information.</u>

<u>B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>

<u>B. </u>How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

<u>45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

6 0
3 years ago
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