Question

SOLVE.

Answer 1

$1.\\4e-15=4e+11\qquad|-4e\\-15=11\qquad FALSE\\\\no\ solution\\-----------------------------\\2.\\3(2f-1)=5(f+2)\qquad|\text{use distributive property}\\(3)(2f)+(3)(-1)=(5)(f)+(5)(2)\\6f-3=5f+10\qquad|+3\\6f=5f+13\qquad|-5f\\\boxed{f=13}\\--------------------------------\\3.\\6g-9=3(2g-3)\qquad|\text{use distributive property}\\6g-9=(3)(2g)+(3)(-3)\\6g-9=6g-9\qquad|-6g\\-9=-9\qquad TRUE\\\\identity\ equation\\--------------------------------------$

$4.\\3(2h-1)=5h-3\qquad|\text{use distributive property}\\(3)(2h)+(3)(-1)=5h-3\\6h-3=5h-3\qquad|+3\\6h=5h\qquad|-5h\\\boxed{h=0}\\------------------------------------\\5.\\4-(3j+2)=2(1-2j)+5\qquad|\text{use distributive property}\\4-3j-2=(2)(1)+(2)(-2j)+5\\4-3j-2=2-4j+5\qquad|\text{combine like terms}\\(4-2)-3j=(2+5)-4j\\2-3j=7-4j\qquad|-2\\-3j=5-4j\qquad|+4j\\\boxed{j=5}$