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3 years ago

What is the method for this (X+1) squared

Mathematics

2 answers:

Alexeev081 [22]3 years ago

8 0

Distribution since you are squaring both

sladkih [1.3K]3 years ago

7 0

(X+1)^2
=(x+1)(x+1)
=(x*(x+1))+(x+1)
=x^2 +x+x+1
=x^2 +2x +1

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Lana71 [14]

Answer: 49.2 cm

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3 years ago

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BigorU [14]

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2 years ago

If limx→3f(x)=7, which of the following must be true? I. f is continuous at x = 3 II. f is differentiable at x = 3

Viktor [21]

Without knowing anything else about $f(x)$ , neither of these need be true.

Suppose

$f(x)=|x-3|+7=\begin{cases}10-x&\text{for }x3\\0&\text{for }x=3\end{cases}$

Then (I) isn't true because, while the limit exists as $x\to3$ and is equal to 7, we have $f(3)=0\neq7$ , so $f(x)$ is not continuous there.

(II) also true because $f(x)$ is not differentiable at $x=3$ ; that is,

$\displaystyle\lim_{x\to3^-}f'(x)=\lim_{x\to3}(10-x)'=\lim_{x\to3}(-1)=-1$

but

$\displaystyle\lim_{x\to3^+}f'(x)=\lim_{x\to3}(x+4)'=\lim_{x\to3}1=1$

which means the derivative does not exist at $x=3$ .

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3 years ago

The height of a trapezoid can be expressed as x-4, while the bases can be expressed as x+4 and x+9. If the area of the trapezoid

hram777 [196]

Check the picture below.

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{bases}{parallel~sides}\\ \cline{1-1} h= x - 4\\ a = x+4\\ b=x+9\\ A=99 \end{cases}\implies 99=\cfrac{(x-4)[(x+4)+(x+9)]}{2} \\\\\\ 99=\cfrac{(x-4)[2x+13]}{2}\implies 198=\stackrel{\mathbb{FOIL}}{2x^2+5x-52}\implies 0=2x^2+5x-250$

$\bf 0=(2x+25)(x-10)\implies x= \begin{cases} ~~\begin{matrix} -25 \\[-0.6em]\cline{1-1}\\[-5pt]\end{matrix}~~\\ 10 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{larger base}}{x+9}\implies 10+9\implies 19$

keeping in mind that "x" cannot be equal to -25, since that'd give us negative values on either base and the bases are a positive value.

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2 years ago

Read 2 more answers

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pogonyaev

I do believe it's 273,972 years.

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