A box contains 8 yellow, 3 orange and 5 purple candies. A tray contains 7 red, 4 blue and 9 orange drinks. If Asia chooses one c
andy and one drink without looking, what is the probability that she will get a yellow candy and not an orange drink. Give your answer as a simplified fraction. (Please help and if you can, show your work so I can learn from it. Thanks so much in advance!)
Okay so we have to first find the total. 8+3+5= 16 candies 7+4+9= 20 drinks Since she wants to get a yellow candy and any drink but orange, put that information as a fraction. 8/16= 50% or 1/2 11/20= 55% (By the way you get 11 because of the 7 red and 4 blue). And that's your answer! Hope this helped and good luck! ^=^
