A box contains 8 yellow, 3 orange and 5 purple candies. A tray contains 7 red, 4 blue and 9 orange drinks. If Asia chooses one c

Question

2 years ago

11

A box contains 8 yellow, 3 orange and 5 purple candies. A tray contains 7 red, 4 blue and 9 orange drinks. If Asia chooses one c

andy and one drink without looking, what is the probability that she will get a yellow candy and not an orange drink. Give your answer as a simplified fraction.
(Please help and if you can, show your work so I can learn from it. Thanks so much in advance!)

Mathematics

1 answer:

gayaneshka [121] · Answer 1 · 2022-02-18T05:51:34+03:00

Okay so we have to first find the total.
8+3+5= 16 candies
7+4+9= 20 drinks
Since she wants to get a yellow candy and any drink but orange, put that information as a fraction.
8/16= 50% or 1/2
11/20= 55% (By the way you get 11 because of the 7 red and 4 blue).
And that's your answer!
Hope this helped and good luck! ^=^