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3 years ago

Find the output, y, when the input, x, is 666.

Mathematics

1 answer:

nata0808 [166]3 years ago

4 0

Answer:

y = 8

Step-by-step explanation:

The question is simply asking for the y-value when x = 6. We look at the graph when x = 6 and see what y-value it gives us. We find that when x = 6, we have y = 8.

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I NEED HELP IN THIS QUESTION PLEASE

IRISSAK [1]

20:) because if you round 19 the nine makes the 1 a 2 lol

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3 years ago

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What is the solution to the equation 4 + 3sqrt 2y = 6?

mojhsa [17]

Answer:

4+3√2y = 6

3√2y = -4+6

3√2y = 2

(3√2y)2 = (2)2

18y = 4

Add 4 to both sides

18y = 4

Divide both sides by 18

A possible solution is :

y = (2/9)

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3 years ago

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Identify the terms and like terms in the expression. x² - 3x + 4 + 2x² - x - 12. Thank you to anyone who helps, I appreciate it

marta [7]

Given:

The expression is:

$x^2-3x+4+2x^2-x-12$

To find:

The terms and like terms in the expression.

Solution:

Terms: Variables, constants and product of variable and constants are known as terms which are separated by addition sign "+".

Like terms: The terms which contain same variables with same power are known as like terms.

The given expression is:

$x^2-3x+4+2x^2-x-12$

It can be rewritten as:

$x^2+(-3x)+4+2x^2+(-x)+(-12)$

Terms are $x^2,-3x,4,2x^2,-x,-12$ .

Like terms are $x^2,2x^2$ and $-3x,-x$ and $4,-12$ .

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3 years ago

One year, in school A, 162 students leave and 109 go to university. In school B, 75 students leave and 68 go to university. Comp

eduard

Answer:

in school a , 67.3 % of leaving students go to university.

in school b ,90.7% of leaving students go to university

Step-by-step explanation:

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3 years ago

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You and another person are sunbathing on the beach near a lifeguard station. The other person chooses a spot that is the same di

Schach [20]

Answer: 26.8 feet

Step-by-step explanation:

In the figure attached you can see two right triangles triangle ABD and a triangle ACD.

You are located at point B and the other person at point C.

The approximate height of the lifeguard station is x.

Keep on mind that:

$tan\alpha=\frac{opposite}{adjacent}$

Therefore:

For the triangle ABD:

$tan(36\°)=\frac{x}{DC+11}$ [EQUATION 1]

For the triangle ACD:

$tan(46\°)=\frac{x}{DC}$ [EQUATION 2]

Solve from DC from [EQUATION 2]:

$DC=\frac{x}{tan(46\°)}$

Substitute into [EQUATION 1] and solve for x:

$tan(36\°)=\frac{x}{(\frac{x}{tan(46\°)}+11)}\\tan(36\°)(\frac{x}{tan(46\°)}+11)=x\\11*tan(36\°)=x-\frac{xtan(36\°)}{tan(46\°)}\\7.991=0.298x$

$x=26.81ft$ ≈26.8ft

7 0

3 years ago