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4 years ago

What kind of tide happens during a last quarter moon? Spring tide Neap tide Extreme tide Low tide

Physics

2 answers:

KIM [24]4 years ago

5 0

I'm pretty sure its a Neap Tide.

Ugo [173]4 years ago

4 0

The answer is the third choice, or letter C. Neap tide

This is because the sun and moon are at right angles to each other. When this happens, the bulge of the ocean caused by the sun partially cancels out the bulge of the ocean caused by the moon. This produces moderate tides known as neap tides, meaning that high tides are a little lower and low tides are a little higher than average. Neap tides occur during the first and third quarter moon

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The closest star to our solar system is Alpha Centauri, which is 4.12 × 10^16 m away. How long would it take light from Alpha Ce

bonufazy [111]

Time = (distance) / (speed)

Time = (4.12x10^16 m) / (3 x10^8 m/s)

Time = 1.37 x 10^8 seconds

Divide the seconds by 86,400 to get days. Then divide the days by 365 to get years.

Time = about 4.35 years

4 0

3 years ago

A vessel (see the figure) comprises of into two chambers

r-ruslan [8.4K]

Answer:

Explanation:

Ideal gas law states:

PV = nRT

n (the number of moles) and R (ideal gas constant) are constant, so we can say:

(PV / T) before = (PV / T) after

Chamber X starts at pressure P, volume V, and temperature T. At equilibrium, the pressure is Px, the volume is Vx, and temperature 3T.

PV / T = Px Vx / 3T

Chamber Y starts at pressure P, volume V, and temperature T. At equilibrium, the pressure is Py, the volume is Vy, and temperature T.

PV / T = Py Vy / T

Substituting and simplifying:

Px Vx / 3T = Py Vy / T

Px Vx / 3 = Py Vy

Since the chambers are at equilibrium, Px = Py:

Vx / 3 = Vy

Vx = 3 Vy

The total volume is the same as before, so:

Vx + Vy = 2V

Substituting:

(3 Vy) + Vy = 2V

4 Vy = 2V

Vy = V / 2

Now if we substitute into our equation for chamber Y:

PV / T = Py (V/2) / T

PV = Py (V/2)

Py = 2P

The pressure in chamber Y (and chamber X) doubles at equilibrium.

4 0

4 years ago

A 10 g bullet is fired into, and embeds itself in, a 2 kg block attached to a spring with a force constant of 19.6 n/m and whose

dmitriy555 [2]

Answer:

$x=0.478\ m$ is the compression in the spring

Explanation:

Given:

mass of the bullet, $m=10\ g=0.01\ kg$

mass of block, $M=2\ kg$

stiffness constant of the spring, $k=19.6\ N.m^{-1}$

initial velocity of the spring just before it hits the block, $u=300\ m.s^{-1}$

Now since the bullet-mass gets embed into the block, we apply the conservation of momentum as:

$m.u=(M+m).v$

$0.01\times 300=(2+0.01)\times v$

$v=1.4925\ m.s^{-1}$

Now this kinetic energy of the combined mass gets converted into potential energy of the spring.

$\rm Kinetic\ energy=Spring\ potential\ energy$

$\frac{1}{2} (M+m).v^2=\frac{1}{2} k.x^2$

$\frac{1}{2} \times (2+0.01)\times 1.4925^2=\frac{1}{2} \times 19.6\times x^2$

$x=0.478\ m$ is the compression in the spring

4 0

3 years ago

Read 2 more answers

What are the properties of a clay pot

Lelechka [254]

PLASTICITY, the MALLEABILITY of the body; extent to which they will absorb water after firing; and SHRINKAGE the extent of revolution in size of a body as water is removed.

There you go!

3 0

3 years ago

a team of dogs is pulling a sled with a net force of 2000 N. The sled is accelerating a 2.2 m/s^2. What is the mass of the sled?

sweet-ann [11.9K]

Force, F = ma

Where m = mass in kg, a = acceleration in m/s², Force, F is in N.

F = ma

2000 = m*2.2

2.2m = 2000

m = 2000/2.2

m ≈ 909.09

Mass is ≈ 909.09 kg.

5 0

3 years ago