The maximum range of the golf ball is 18.6 m.
The given parameters;
height reached by the ball, h = 3 m
distance of the ball, x = 14
the initial velocity of the ball, u = 13.5 m/s
The maximum range of the ball is calculated as follows;
at maximum range, the angle of projection,
Thus, the maximum range of the golf ball is 18.6 m.
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It depends on how much force there both putting on the box but because it does say the correct answer is C.
Answer:
a) T=549.36N Upwards
b) T=448.56N Upwards
c) T=650.16N Upwards
Explanation:
The very first thing we can do to solve this problem is to draw a free body diagram we can use to analyze the situation (see attached picture).
On the diagram we can see there are only two forces acting on the object: the tension of the rope and the weight of the object itself.
a)
Since the object is moving at a constant speed, this means that its acceleration will be zero. So we can do a sum of forces like this:
T-W=0
T=W
T=mg
T=549.36N upwards
b)
For part b, since the object is accelerating downwards, we wil say that it's acceleration is negative, so
so we can do a sum of forces again:
so
T-W=ma
T=ma +W
T=ma+mg
T=m(a+g)
and now we substitute:
which yields:
T=448.56N upwards (in this particular case, the tension always goes upwards)
c)
Since the object is moving upwards, we can say that its acceleration will be positive, so
we can take the solved equation we got on the previous part of the problem, so we get:
T=m(a+g)
which yields:
T=650.16N upwards
Answer:
12
Explanation:
I don't know an explanation used a density calculator
Answer:
63.0 N
Explanation:
We need to consider the resultant of the forces acting along the surface. We have two forces:
- The component of the pull parallel to the ground, which is given by
where is the angle between the force and the ground
- The frictional force, given by
where is the coefficient of friction, m = 20 kg is the mass of the box and g=9.8 m/s^2.
The box is moving at constant velocity, this means zero acceleration, so the equation of equilibrium becomes:
From which we can find the magnitude of the pull, F: