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dlinn [17]
3 years ago
9

When you push a 2.00 kg book resting on a tabletop it takes 4.60 N to start the book sliding. What is the coefficient of static

friction between the book and the tabletop? g
Physics
1 answer:
natali 33 [55]3 years ago
3 0

The coefficient of static friction is 0.234.

Answer:

Explanation:

Frictional force is equal to the product of coefficient of friction and normal force acting on any object.

So here the mass of the object is given as 2 kg, so the normal force will be acting under the influence of acceleration due to gravity.

Normal force = mass * acceleration due to gravity

Normal force = 2 * 9.8 = 19.6 N.

And the frictional force is given as 4.6 N, then

Coefficient of static friction = Frictional force/Normal force

Coefficient of static friction = 4.6 N / 19.6 N = 0.234

So the coefficient of static friction is 0.234.

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An ambulance is traveling east at 61.9 m/s. Behind it there is a car traveling along the same direction at 28.5 m/s. The ambulan
inessss [21]

Answer: 0.4 m

Explanation:

Given

Speed of ambulance, vs = 61.9 m/s

Speed of car = 28.5 m/s

Frequency of ambulance siren, f = 694 Hz

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With speed of ambulance being (61.9 m/s) -> We solve using

fd = f(v + vr) / (v - vs), where vr = 0

fd = 694 * (343 + 0) / (343 - 61.9)

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Recall,

λ = v/f

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7 0
3 years ago
Which of the following best describes the domains of unmagnetized iron?
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A piece of iron can only become a magnet when the magnetic domain aligns.

Since we have an unmagnetized piece of iron, this means that its domain is not aligned. However, this does not mean that the domain does not exist.

Based on the above, the best choice would be:
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8 0
3 years ago
Suppose your walking speed is 2m/s in a period of 1 s . What is your acceleration?
Veronika [31]

Answer:

<h2>2 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

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t is the time taken

From the question we have

a =  \frac{2}{1}  \\

We have the final answer as

<h3>2 m/s²</h3>

Hope this helps you

6 0
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