The coefficient of static friction is 0.234.
Answer:
Explanation:
Frictional force is equal to the product of coefficient of friction and normal force acting on any object.
So here the mass of the object is given as 2 kg, so the normal force will be acting under the influence of acceleration due to gravity.
Normal force = mass * acceleration due to gravity
Normal force = 2 * 9.8 = 19.6 N.
And the frictional force is given as 4.6 N, then
Coefficient of static friction = 4.6 N / 19.6 N = 0.234
So the coefficient of static friction is 0.234.
Answer:
alpha=53.56rad/s
a=5784rad/s^2
Explanation:
First of all, we have to compute the time in which point D has a velocity of v=23ft/s (v0=0ft/s)
Now, we can calculate the angular acceleration (w0=0rad/s)
with this value we can compute the angular velocity
and the tangential velocity of point B, and then the acceleration of point B:
hope this helps!!
solution:
1.6 m/s = 96 m/min (in other words, 1.6 m/s x 60 s/min)
96 m/min x 8.3 min = 796.8 m