All categories

2 years ago

What are the first 4 terms in the sequence represented by the expression 2n+3?

Mathematics

1 answer:

alekssr [168]2 years ago

4 0

Answer:

cccccc

Step-by-step explanation:

hope this helps.

You might be interested in

What is the slope of the line that passes through the points (-7, -7) and (-7, 1)? Write your answer in simplest form.

Ronch [10]

Answer:

undefined, stays on x so straight vertical - vertical line is undef slope

3 0

3 years ago

Read 2 more answers

Five girls decide to share a box of cookies equally. Each girl got for cookies. Right and solve an equation to find out how many

Natalija [7]

Answer:

Step-by-step explanation:

5 * 4 = 20

3 0

3 years ago

The radius of a circle is 1 yard. What is the circle's circumference? r=1 yd

matrenka [14]

Answer:

6.3 yards

Step-by-step explanation:

mathematically, to get the circumference of the circle, we will have to use the formula for the circumference of a circle

we have this as;

C = 2 * pi * r

r is 1 yard

c = 2 * pi * 1 = 2pi yards = 6.3 yards

5 0

2 years ago

Student Council needs $600 for the

s344n2d4d5 [400]

Answer:

<h2>MARK ME AS BRAINLY</h2>

<h3>#Carry On Learning</h3><h3 />

3 0

3 years ago

Given that 'n' is a natural number. Prove that the equation below is true using mathematical induction.

LenaWriter [7]

<h3>To ProvE :- </h3>

1 + 3 + 5 + ..... + (2n - 1) = n²

Method :-

If P(n) is a statement such that ,

P(n) is true for n = 1
P(n) is true for n = k + 1 , when it's true for n = k ( k is a natural number ) , then the statement is true for all natural numbers .

$\sf\to \textsf{ Let P(n) : 1 + 3 + 5 + $\dots$ +(2n-1) = n$^{\sf 2}$ }$

Step 1 : Put n = 1 :-

$\sf\longrightarrow LHS = \boxed{\sf 1 } \\$

$\sf\longrightarrow RHS = n^2 = 1^2 = \boxed{\sf 1 }$

Step 2 : Assume that P(n) is true for n = k :-

$\sf\longrightarrow 1 + 3 + 5 + \dots + (2k - 1 ) = k^2$

Add (2k +1) to both sides .

$\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1)=k^2+(2k+1)$

RHS is in the form of ( a + b)² = a²+b²+2ab .

$\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1)= (k +1)^2$

Adding and subtracting 1 to LHS .

$\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1) + 1 -1 = (k +1)^2 \\$

$\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+2) - 1 = (k +1)^2$

Take out 2 as common .

$\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+\{2(k+1)-1\}= (k +1)^2$

P(n) is true for n = k + 1 .

Hence by the principal of Mathematical Induction we can say that P(n) is true for all natural numbers 'n' .

**Edits are welcomed**

8 0

2 years ago

Read 2 more answers