Ask question

Ask question

All categories

3 years ago

13

Solve for x. 9 ≤ 17 − 4x

2 answers:

Pani-rosa [81]3 years ago

6 0

If you would like to solve 9 <= 17 - 4x for x, you can do this using the following steps:

9 <= 17 - 4x
4x <= 17 - 9
4x <= 8 /4
x <= 8/4
x <= 2

The correct result would be x <= 2.

anygoal [31]3 years ago

3 0

$\sf 9 \leq 17-4x\\Add\ 4x\ to\ both\ sides.\\4x+9 \leq 17\\Subtract\ 9\ from\ both\ sides.\\4x \leq 8\\Divide\ by\ 2\ on\ both\ sides.\\x \leq 2\\\\\\{\boxed{x \leq 2}$

You might be interested in

Lynn has a watering can that holds 32 cups of water, and she fills it a quarter full. Then she waters her 23 plants so that each

Arlecino [84]

.3478 is the answer, round however you like

6 0

3 years ago

The shelter has 90 dogs and 150 cats. of these animals 9 dogs and 27 cats receive medication. What percentage of animals receive

krek1111 [17]

3% because If you divide 27/9

4 0

3 years ago

Which properties are best used prove a quadrilateral is a square?

adell [148]

Answer:

a, b, c, & d

Step-by-step explanation:

8 0

3 years ago

If a die is rolled one time, find probability of getting a number greater than 3 and an odd number.

Nadya [2.5K]

Answer:

$\dfrac{1}{6}$ .

Step-by-step explanation:

It is given that a die is rolled one time. So,

Sample space : $S=\{1,2,3,4,5,6\}$

Number is greater than 3 : $A=\{4,5,6\}$

Number is odd : $A=\{1,3,5\}$

Number greater than 3 and an odd number : $A\cap B=\{5\}$

It is conclude that,

$n(S)=6, n(A)=3,n(B)=3,n(A\cap B)=1$

The probability of getting a number greater than 3 and an odd number is

$P=\dfrac{n(A\cap B)}{n(S)}$

$P=\dfrac{1}{6}$

Therefore, the required probability is $\dfrac{1}{6}$ .

4 0

3 years ago

Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe

Deffense [45]

A calculator shows
$\dfrac{\sqrt{-9}}{(4-7i)-(6-6i)}=\dfrac{3i}{-2-i}=-3\cdot\dfrac{i(2-i)}{2^2+1^2}\\\\=\dfrac{-3-6i}{5}$

8 0

3 years ago