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Sholpan [36]
2 years ago
10

Why is it to hor in the stadium after the game

Mathematics
1 answer:
aleksandrvk [35]2 years ago
4 0

Answer:

because all the fans have left

Step-by-step explanation:

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RESUELVE... A. 4X + 5X, B. -3X-2X
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I don't recognize this problem, please make sure the input is complete.
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Find the equation of the line that passes through (3,-4) and is parallel to 3x+y+2=0
miskamm [114]

Answer:

y=-3x+5

Step-by-step explanation:

it parallel to 3x+y+2=0 => line is: 3x+y+c=0

It through (3;-4) => 3(3)+(-4)+c=0 <=> c=-5

Line is 3x+y-5=0 => y=-3x+5

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3 years ago
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A single card is drawn at random from a standard 52 card deck. Work out in its simplest
larisa [96]

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1/52

Step-by-step explanation:

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3 years ago
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It is 0.30 or in words, 30 hundredth.

Step-by-step explanation:

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3 years ago
What eigen value for this matix <br> (1 -2)<br> (-2 0)
natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

5 0
2 years ago
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