1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kolbaska11 [484]
3 years ago
5

There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th

e tags for the eight jobs are:
{LPW,QKJ,CDP,USU,BBD,PST,LSA,RHR}

a. How many different ways are there to order the eight jobs in the queue?
b. How many different ways are there to order the eight jobs in the queue so that job USU comes immediately before CDP?
c. How many different ways are there to order the eight jobs in the queue so that job USU comes somewhere before CDP in the queue, although not necessarily immediately before?
d. How many different ways are there to order the eight jobs in the queue so that either QKJ or LPW come last?
e. How many different ways are there to order the eight jobs in the queue so that QKJ is either last or second-to-last?
Mathematics
1 answer:
Vikentia [17]3 years ago
5 0

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

You might be interested in
<img src="https://tex.z-dn.net/?f=%5Chuge%5Cfbox%5Cpurple%7BQuestion%7D" id="TexFormula1" title="\huge\fbox\purple{Question}" al
ICE Princess25 [194]

The LCM of the given numbers have been determined.

<h3>What is LCM ?</h3>

LCM stands for Least Common Multiple .

For two numbers , LCM is the number that is the smallest number of which they both are a factor.

It is asked to determine

LCM of 6 and 9

6 = { 6 , 12 , 18 , 24 , 30 , 36 , 42 .....}

9 = { 9 , 18 ,27 .....}

The LCM of 6 , 9 is 18

LCM of 8 and 12

8 = { 8,16,24,32....}

12 = {12 , 24 ,36....}

The LCM of 8 and 12 is 24

LCM of 4 , 6 and 8

4 = {4 , 8 , 12 , 16 , 20,24,28 ....}

6 = { 6 ,12 ,18,24......}

8 = {8 , 16,24 .....}

The LCM of 4,6 and 8  is 24

The LCM of 6 and 15 is 30  

The LCM of 20 and 30 is  60

The LCM of 25,30 and 75 is 150

The image of the solution is attached .

To know more about LCM

brainly.com/question/20739723

#SPJ1

6 0
2 years ago
Help me please! Thanks
Sunny_sXe [5.5K]
Hope this helps! have a nice day/night

8 0
3 years ago
(1 point) A tank contains 2640 L of pure water. A solution that contains 0.09 kg of sugar per liter enters the tank at the rate
OverLord2011 [107]

Answer:

t=0      Sugar = 0 Kg

t=1min Sugar=0.27 Kg

Step-by-step explanation:

Data

Tank = 2640 L (pure water)

Sol=0.09kg Sugar per liter

Vin = Vout = 3L/min

Sugar in the beginning = ?

if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water , but if beginning is t= 1min then;

\frac{3L}{min}*\frac{0.09Kg}{L}=0.27kg/min

7 0
3 years ago
Read 2 more answers
Help!!!!¡¡¡¡ i need help solving this it will increase my letter grade!!!!
Shtirlitz [24]

Answer:

The answer is below⬇️⬇️

Step-by-step explanation:

f(x) = 3x+4

g(x) = 2x

h(x) = x²+x-2

g(hx) = 2(x²+x-2)

= 2x²+2x-4

f(g(hx))=3(2x²+2x-4)+4

=6x²+6x-12+4

=6x²+6x-8

g(f(g(hx)))=2(6x²+6x-8)

=12x²+12x-16

f(g(f(g(hx))))=3(12x²+12x-16)+4

=36x²+36x-48+4

=36x²+36x-44

h(f(g(f(g(hx)))))=(36x²+36x-44)²+36x²+36x-44-2

=1296x⁴+2592x³-1872x²-3168x+1936+36x²+36x-46

=1296x⁴+2592x³-1836x²-3132x+1890

f(h(f(g(f(g(hx))))))=3(1296x⁴+2592x³-1836x²-3132x+1890)+4

=3888x⁴+7776x³-5508x²-9396x+5674

h(f(h(f(g(f(g(hx)))))))=(3888x⁴+7776x³-5508x²-9396x+5674)²+3888x⁴+7776x³-5508x²-9396x+5674-2

=15116544x⁸+60466176x⁷+17635968x⁶-158723712x⁵-71663616x⁴+657591048x³-255531048x²-106635204x+32194276

6 0
3 years ago
the weight of a full steel bead tire is approximately 800 grams, while a fighter wheel weighs only 700 grams. what is the weight
Wittaler [7]
The answer is 1,800.
7 0
3 years ago
Other questions:
  • When making pink paint, the art teacher uses the ratio 3:2. For every 3 cups of white paint she uses in the mixture, she needs t
    12·1 answer
  • Put these in greatest to least:
    13·1 answer
  • If two solids are similar and the ratio between the lengths of their edges is 2;7 what is the ratio of their volumes?
    8·1 answer
  • there are 112 students going on a field trip to pan for gold if they are going in vans that hold 6 students eat how many Vans ar
    15·1 answer
  • Find the values of x, y, and z for which ABCD must be a parallelogram.
    14·1 answer
  • Olve the system of equations.
    10·1 answer
  • How do you find the r?
    12·2 answers
  • Jessie estiments the weight of her cat to be 10 pounds the actual weight of the cat is 13.75 pounds fine the percent error
    13·1 answer
  • I need help with this question
    10·1 answer
  • 50 POINTS
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!