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MArishka [77]
3 years ago
12

Can you help with this one

Mathematics
1 answer:
Daniel [21]3 years ago
7 0
The one that has less volume is cereal box b because as you can see the box is 12 inches so it's smaller so it might as well has less volume. Hope this help
You might be interested in
Evaluate the expression you got in part f for d = 5.
Triss [41]

Answer:

Before you get started, take this readiness quiz.

Is n÷5 an expression or an equation? If you missed this problem, review Example 2.1.4.

Simplify 45. If you missed this problem, review Example 2.1.6.

Simplify 1+8•9. If you missed this problem, review Example 2.1.8.

Evaluate Algebraic Expressions

In the last section, we simplified expressions using the order of operations. In this section, we’ll evaluate expressions—again following the order of operations.

To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number. To evaluate an expression, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations.

Example 2.3.1: evaluate

Evaluate x+7 when

x=3

x=12

Solution

To evaluate, substitute 3 for x in the expression, and then simplify.

x+7

Substitute.

3+7

Add.

10

When x=3, the expression x+7 has a value of 10.

To evaluate, substitute 12 for x in the expression, and then simplify.

x+7

Substitute.

12+7

Add.

19

When x=12, the expression x+7 has a value of 19. Notice that we got different results for parts (a) and (b) even though we started with the same expression. This is because the values used for x were different. When we evaluate an expression, the value varies depending on the value used for the variable.

exercise 2.3.1

Evaluate: y+4 when

y=6

y=15

Answer a

Answer b

exercise 2.3.2

Evaluate: a−5 when

a=9

a=17

Answer a

Answer b

Example 2.3.2

Evaluate 9x−2, when

x=5

x=1

Solution

Remember ab means a times b, so 9x means 9 times x.

To evaluate the expression when x=5, we substitute 5 for x, and then simplify.

9x−2

Substitute 5 for x.

9⋅5−2

Multiply.

45−2

Subtract.

43

To evaluate the expression when x=1, we substitute 1 for x, and then simplify.

9x−2

Substitute 1 for x.

9⋅1−2

Multiply.

9−2

Subtract.

7

Notice that in part (a) that we wrote 9•5 and in part (b) we wrote 9(1). Both the dot and the parentheses tell us to multiply.

exercise 2.3.3

Evaluate: 8x−3, when

x=2

x=1

Answer a

Answer b

exercise 2.3.4

Evaluate: 4y−4, when

y=3

y=5

Answer a

Answer b

Example 2.3.3: evaluate

Evaluate x2 when x=10.

Solution

We substitute 10 for x, and then simplify the expression.

x2

Substitute 10 for x.

102

Use the definition of exponent.

Evaluate: 2x when x=6.

Answer

exercise 2.3.8

Evaluate: 3x when x=4.

Answer

Example 2.3.5: evaluate

Evaluate 3x+4y−6 when x=10 and y=2.

Solution

This expression contains two variables, so we must make two substitutions.

3x+4y−6

Substitute 10 for x and 2 for y.

3(10)+4(2)−6

Multiply.

30+8−6

Add and subtract left to right.

32

When x=10 and y=2, the expression 3x+4y−6 has a value of 32.

exercise 2.3.9

Evaluate: 2x+5y−4 when x=11 and y=3

Answer

exercise 2.3.10

Evaluate: 5x−2y−9 when x=7 and y=8

Answer

Example 2.3.6: evaluate

Evaluate 2x2+3x+8 when x=4.

Solution

We need to be careful when an expression has a variable with an exponent. In this expression, 2x2 means 2•x•x and is different from the expression (2x)2, which means 2x•2x.

2x2+3x+8

Substitute 4 for each x.

2(4)2+3(4)+8

Simplify 42.

2(16)+3(4)+8

Multiply.

32+12+8

Add.

52

exercise 2.3.11

Evaluate: 3x2+4x+1 when x=3.

Answer

exercise 2.3.12

Evaluate: 6x2−4x−7 when x=2.

Answer

Identify Terms, Coefficients, and Like Terms

Algebraic expressions are made up of terms. A term is a constant or the product of a constant and one or more variables. Some examples of terms are 7, y, 5x2, 9a, and 13xy.

8 0
3 years ago
How many more points do I need for a gpa of a 2.0<br>​
madreJ [45]

Answer:

you need at least a score of 60

Step-by-step explanation:

anything 59 and below is 1.95 and every percent higher it adds .5 more

8 0
2 years ago
Read 2 more answers
Please help!!!! got to do this for math
Umnica [9.8K]

Answer:

11\sqrt{2}-5\sqrt{7}

7 0
3 years ago
A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit
aliina [53]

Answer: All possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

2x+9y=101

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

7 0
2 years ago
The basketball players at
kupik [55]
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