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Arturiano [62]
3 years ago
8

In one revolution a circle covers a distance equal to its

Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

c

c

c

c

c

c

c

c

c

c

c

c

c

c

c

c

c

c

cc

c

c

balandron [24]3 years ago
4 0

the answer is C The distance covered in one revolution is equal to circumference of the circle.

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What is the solution to the system of equations shown below? 3x+8y=−18 6x+16y=−54
Olin [163]

Answer:

79

Step-by-step explanation:

5 0
3 years ago
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For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?
n200080 [17]
<h3>Answer:  k = 0 or k = 3</h3>

Explanation:

If you have repeated x values, then you wont have a function. For example, the points (1,5) and (1,6) mean we don't have a function since the input x = 1 leads to multiple outputs y = 5 and y = 6 simultaneously. For a function to be possible, we must have any input lead to exactly one output only.

What we do is set the x coordinates (k^2 and 3k) equal to each other and solve for k

k^2 = 3k

k^2-3k = 0

k(k-3) = 0 .... factoring

k = 0 or k-3 = 0 .... zero product property

k = 0 or k = 3

If k = 0, then (k^2,5) becomes (0,5). Also, (3k,6) becomes (0,6). The two points (0,5) and (0,6) mean the graph fails the vertical line test.

Similarly, if k = 3, then (k^2,5) becomes (9,5) and (3k,6) = (9,6). Another vertical line test failure happens here to show we don't have a function.

7 0
4 years ago
You start at (4, 6). You move right 6 units and left 6 units. Where do you end?
Sergio039 [100]

Answer:

4,6

Step-by-step explanation:

Good Luck =)

7 0
3 years ago
Divide the following
kozerog [31]
Factor the numerator and denominator and cancel the common factors. 
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5 0
3 years ago
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A bookmark is shaped like a rectangle with a semicircle attached at both ends. The rectangle is 16 cm long and 4 cm wide. The di
Sedaia [141]

Answer: 76.56sqcm

Step-by-step explanation:

Area of rectangle= length * width

= 16 * 4 = 64sqcm

Area of semicircle= (1/2)(r^2)π

r= d/2= 4/2= 2

Area of semicircle= (1/2)(2^2)(3.14)

= 6.28sqcm

Area of bookmark= Area of rectangle + 2*Area of semicircle

Area of bookmark= 64 + 2(6.28)

=64 + 12.56 = 76.56sqcm

3 0
3 years ago
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