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Arturiano [62]
3 years ago
8

In one revolution a circle covers a distance equal to its

Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

c

c

c

c

c

c

c

c

c

c

c

c

c

c

c

c

c

c

cc

c

c

balandron [24]3 years ago
4 0

the answer is C The distance covered in one revolution is equal to circumference of the circle.

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Helppppppp please, all math lovers I'm calling for you​
Katen [24]

Answer:

Dive by n square root two, also option one.

Step-by-step explanation:

The first step to any algebra equation is to isolate the variable and you do that by divide square root 2 since it cancels out on the left side and now n is alone.

Hoped that helped :)

8 0
3 years ago
A ramp has a rise of 10 feet and run of 50 feet find the slope
Goshia [24]
Slope = rise/run = 10/50 = 1/5
7 0
3 years ago
Read 2 more answers
Mike is making a nut mixture for an upcoming camping trip. He makes the mixture by combining of a cup of cashews and of a cup of
vitfil [10]
28 ÷ 2 = 14. you need 14 cups of each nut to get a total of 28 cups combined
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3 years ago
Read 2 more answers
State the range of the relation
Finger [1]

The range of the given relation is D. R = {-1, 3, 5, 8}.

Step-by-step explanation:

Step 1:

The range of a relation is the second set of values while the domain constitutes the first set of values.

There are 4 given relations with two sets of values so there would be 4 domain values and 4 range values.

Step 2:

The range of (1, -1) = -1,

The range of (2, 3) = 3,

The range of (3, 5) = 5,

The range of (4, 8) = 8.

Combining these values we get the range as {-1, 3, 5, 8} which is option D.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B
ankoles [38]

\bold{Heya!}

Your answer to this is:

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u />\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)

\sf{Apply \: rule:} \: (a) = a

\sf{(1) = 1

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1

\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}

\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

Hopefully This Helps ! ~

#LearnWithBrainly

\underline{Answer :}

<em>Jaceysan ~</em>

7 0
2 years ago
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