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3 years ago

In one revolution a circle covers a distance equal to its

Mathematics

2 answers:

DIA [1.3K]3 years ago

6 0

Answer:

balandron [24]3 years ago

4 0

the answer is C The distance covered in one revolution is equal to circumference of the circle.

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Helppppppp please, all math lovers I'm calling for you

Katen [24]

Answer:

Dive by n square root two, also option one.

Step-by-step explanation:

The first step to any algebra equation is to isolate the variable and you do that by divide square root 2 since it cancels out on the left side and now n is alone.

Hoped that helped :)

8 0

3 years ago

A ramp has a rise of 10 feet and run of 50 feet find the slope

Goshia [24]

Slope = rise/run = 10/50 = 1/5

7 0

3 years ago

Read 2 more answers

Mike is making a nut mixture for an upcoming camping trip. He makes the mixture by combining of a cup of cashews and of a cup of

vitfil [10]

28 ÷ 2 = 14. you need 14 cups of each nut to get a total of 28 cups combined

7 0

3 years ago

Read 2 more answers

State the range of the relation

Finger [1]

The range of the given relation is D. R = {-1, 3, 5, 8}.

Step-by-step explanation:

Step 1:

The range of a relation is the second set of values while the domain constitutes the first set of values.

There are 4 given relations with two sets of values so there would be 4 domain values and 4 range values.

Step 2:

The range of (1, -1) = -1,

The range of (2, 3) = 3,

The range of (3, 5) = 5,

The range of (4, 8) = 8.

Combining these values we get the range as {-1, 3, 5, 8} which is option D.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B

ankoles [38]

$\bold{Heya!}$

Your answer to this is:

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u /> $\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)$

$\sf{Apply \: rule:} \: (a) = a$

$\sf{(1) = 1$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1$

$\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}$

$\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

Hopefully This Helps ! ~

#LearnWithBrainly

$\underline{Answer :}$

<em>Jaceysan ~</em>

7 0

2 years ago