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Snowcat [4.5K]
3 years ago
7

What is the equation of the line that passes through the point (3,-3)(3,−3) and has a slope of 0?

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

The equation of the line that passes through the point (3,-3) and has a slope of 0 will be:

0=y+3

Step-by-step explanation:

The point-slope form of the equation of a line is:

\:y\:-\:y_1\:=\:m\left(x-x_1\right)

where

  • m is the slope of the line and,
  • \left(x_1,\:y_1\right) is a point on the line.

As the slope is m=0, and the point is (3,-3)

so

Equation of the line will be:

\:y\:-\:y_1\:=\:m\left(x-x_1\right)

y\:-\:\left(-3\right)\:=\:0\left(x-3\right)

Further simplifying

0=y-\left(-3\right)

0=y+3

Therefore, the equation of the line that passes through the point (3,-3) and has a slope of 0 will be:

0=y+3

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a=(∑y)(∑x²)-(∑x)(∑xy) / n(∑x²)-(∑x)² where n is number of samples

b= n(∑xy)-(∑x)(∑y) / n(∑x²)-(∑x)²

Form a table like below

<u>x                     y               xy               x²                 y²</u>

14                   12              168            196              144

1                      3                 3               1                   9

6                     6                 36            36                 36

5                     7                 35             25                49

10                    7                 70             100              49

6                      8                 48             36              64

11                      9                99             121               81

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f) r² is important because it shows you the proportion of the variance of one variable that is predictable from the other variable.

r=0.6996

r²=0.6996² =0.4894

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