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3 years ago

What is the equation of the line that passes through the point (3,-3)(3,−3) and has a slope of 0?

Mathematics

1 answer:

hichkok12 [17]3 years ago

8 0

Answer:

The equation of the line that passes through the point (3,-3) and has a slope of 0 will be:

$0=y+3$

Step-by-step explanation:

The point-slope form of the equation of a line is:

$\:y\:-\:y_1\:=\:m\left(x-x_1\right)$

where

$m$ is the slope of the line and,
$\left(x_1,\:y_1\right)$ is a point on the line.

As the slope is $m=0$ , and the point is $(3,-3)$

Equation of the line will be:

$\:y\:-\:y_1\:=\:m\left(x-x_1\right)$

$y\:-\:\left(-3\right)\:=\:0\left(x-3\right)$

Further simplifying

$0=y-\left(-3\right)$

$0=y+3$

Therefore, the equation of the line that passes through the point (3,-3) and has a slope of 0 will be:

$0=y+3$

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