Scatter light doesn't reflect, reflect light goes off a mirror.
The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm
We will apply:
Q = mcΔT; where Q is the heat, m is the mass, c is the specific heat capacity and ΔT is the temperature change.
30,000 = 390 x 3.9 x ΔT
ΔT = 19.7 °C
The temperature change is of 19.7 °C.
You probably know this equation giving the power dissipated:
P = IV
P = power, I = current, V = applied voltage
We can substitute I = V/R from Ohm's law:
P = V²/R
Given values:
V = 30.0×10³V, R = 0.40Ω/km×34.0km = 13.6Ω
Plug in and solve for P:
P = (30.0×10³)²/13.6
P = 6.62×10⁷W
