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Sever21 [200]
3 years ago
7

A proton is trapped in a one-dimensional well that is 200 pm wide. What is the ground state energy of the proton, if the potenti

al is zero at the bottom of the well?
Physics
1 answer:
Harrizon [31]3 years ago
8 0

Answer:

E=1.50\times 10^{-18}J

Explanation:

Energy of the one dimensional infinite well,

E=\frac{n^{2}h^{2} }{8mL^{2} }

Given that, L=200 pm\\L=200\times 10^{-12}m

For the ground state n=1,

Therefore energy is,

E=\frac{(6.626\times 10^{-34})^{2}}{8(9.1\times 10^{-31})(200\times 10^{-12}) ^{2} }\\E=1.50\times 10^{-18}J

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