Question

A proton is trapped in a one-dimensional well that is 200 pm wide. What is the ground state energy of the proton, if the potential is zero at the bottom of the well?

Answer 1

Answer:

E=1.50\times 10^{-18}J

Explanation:

Energy of the one dimensional infinite well,

$E=\frac{n^{2}h^{2} }{8mL^{2} }$

Given that, $L=200 pm\\L=200\times 10^{-12}m$

For the ground state n=1,

Therefore energy is,

$E=\frac{(6.626\times 10^{-34})^{2}}{8(9.1\times 10^{-31})(200\times 10^{-12}) ^{2} }\\E=1.50\times 10^{-18}J$