Answer:
a) t = 4.14 s
b) Speed with which it hits the ground = 40.58 m/s
Explanation:
Using the equations of motion,
g = 9.8 m/s², y = H = 84 m,
Initial velocity, u = 0 m/s,
final velocity, v = ?
Total Time of fall, t = ?
a) y = ut + gt²/2
84 = 0 + 9.8t²/2
4.9t² = 84
t² = 84/4.9
t = 4.14 s
b) v = u + gt
v = 0 + (9.8 × 4.14)
v = 40.58 m/s
Answer: Graphing data is used to display data because it is easier to see trends in the data when it is displayed visually compared to when it is displayed numerically in a table.
Your question has no context, nobody’s going to be able to answer it.
Answer:
1.267 nanometers.
Explanation:
From the question,
Speed = distance/time.
S = d/t.................. Equation 1
Make d the subject of the equation,
d = S×t ............................... Equation 2
Given: S = 4.0 cm/year, t = 1 seconds = 3.17×10⁻⁸ years
Substitute into equation 2
d = 4×3.17×10⁻⁸ =
12.68×10⁻⁸ cm = 12.67×10⁻⁸×10⁷
d = 1.267 nanometers.
Hence the Tectonic plates move 1.267 nanometers.
