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rodikova [14]
3 years ago
14

Cara has $25 to buy dry pet food and treats for the animal shelter. A pound of dog food costs $2 and treats are $1 a piece. If s

he buys 9 pounds of food, what is the greatest number of treats she can by?
Mathematics
2 answers:
9966 [12]3 years ago
6 0

Cara starts with 25$.

9 x 2 = 18$

25 - 18 = 7$

Cara can buy 7 dogs treats.

Sidana [21]3 years ago
3 0

9 pounds of food at 2.00= 18.00

she has 25.00-18.00= 6.00 to buy treays

6÷1=6

Cara can buy 6 treats

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In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311
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Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

Z_{1-\alpha /2}= Z_{0.975}= 1.965

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

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Reed bought 1.8 pounds of green beans. The green beans cost $1.27 per pound. What was the total cost of Reed’s green beans? Roun
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Answer:

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Step-by-step explanation:

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So what you would do is 8/5 + 4 x 7 = 26.9
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How to do this 24:96 = 5:?
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Um... I think you meant <span>24:96 = 5:x

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</span>
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