Answer: 3/2 (simplified: 1.5)
Step-by-step explanation:
X=pi
X=3pi/2
Remove pi from both equations because pi will cancel out each other then you will be left with the equation 3/2. So therefore the rate of change would be 3/2 simplified would be 1.5
<u>136 + x + x = 180. Or, to simplify, 136 + 2x = 180. The congruent angles measure 23 degrees each.</u>
We know this because of a simple rule that goes for all triangles: The measures of all three angles in a triangle will <em>always</em> add up to 180 degrees.
One angle of a triangle measures 136 degrees. The other two angles are congruent (have the same measure).
(x stands for an unknown angle measure.) So the equation we would use is 136 + 2x = 180. We can solve this within a few steps.
1. We subtract 136 from 2x in order to isolate 2x. But if we subtract something from the left side of the equation, we have to subtract it from the right side too. Otherwise the equation will be wrong; We would be taking away the balance.
2x = 180 - 136
2. Now that 2x is isolated, we solve 180 - 136.
2x = 46
3. If we know now that 2x is equal to 46, how do we find out what x is equal to? We divide by 2 (on both sides or it'll be wrong) to get x.
2x = 46
2x/2 = 46/2
x = 23
Now we know! x = 23... The other two angles are both 23 degrees. We can check to see if that's right by solving 23 + 23 + 136... Does it add up to 180? Yes! :)
Answer:
f(n)=f(8)-2(8-1)
Step-by-step explanation:
i think this is right
The argument is valid by the law of detachment.

(a)
![f'(x) = \frac{d}{dx}[\frac{lnx}{x}]](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Cfrac%7Blnx%7D%7Bx%7D%5D)
Using the quotient rule:


For maximum, f'(x) = 0;


(b) <em>Deduce:
</em>

<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)


, since ln(e) is simply equal to 1
Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.



Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:


, as required.