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kompoz [17]
3 years ago
14

solve this word problem leading to quadratic equation: the area of a rectangle is 60cm². The length is 11cm more than the width.

Find the width.​
Mathematics
1 answer:
morpeh [17]3 years ago
8 0

Answer:

Step-by-step explanation:

let : x The length and y the width you have this system :

xy =60....(1)

x = y+10...(2)

put the value for x in (1):  (y+10)y =60

the quadratic equation is : y² +10y - 60 = 0

Δ =b² - 4ac        a = 1        b= 10      c= - 60

Δ =10² - 4(1)(-60) = 324 =18²

y 1 = (-10-18)/2 negatif...... refused

y 2 = (-10+18)/2 =4

the width is 4

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ZX is perpendicular bisector of WY if WY=24 what is WX
bixtya [17]

Answer:

12

Step-by-step explanation:

6 0
3 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
It is known that a cable with a​ cross-sectional area of 0.300.30 sq in. has a capacity to hold 2500 lb. If the capacity of the
vesna_86 [32]

Answer:

0.84 square in

Step-by-step explanation:

Since the capacity of the cable is proportional to its​ cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold

2500 / 0.3 = 8333.33 lb/in

To old 7000 lb it the cross-sectional area would need to be

7000 / 8333.33 = 0.84 square in

5 0
3 years ago
Read 2 more answers
What kind of context clue provides the meaning of a word directly in the sentence?
____ [38]

Answer:

The answer is definition.

Hope i helped

3 0
3 years ago
Three times as many children as adults attended a concert on Saturday. An adult ticket cost $7 and a child’s ticket cost $3. The
Ierofanga [76]

For this case we propose a system of equations:

x: Let the variable representing the number of children in the concert

y: Let the variable representing the number of adults at the concert

According to the assistance we have:

x = 3y

According to the cost we have:

3x + 7y = 6000

Substituting the first in the second equation we have:

3 (3y) + 7y = 6000\\9y + 7y = 6000\\16y = 6000\\y = \frac {6000} {16}\\y = 375

Thus, the concert was 375 adults.

On the other hand we have:

x = 3 (375) = 1125

Thus, the concert was 1125 children.

In total they were:

375 + 1125 = 1500 people

ANswer:

The concert was 1500 people

3 0
3 years ago
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