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Marizza181 [45]
3 years ago
14

PLA HELP I'LL MARK BRAINLEST

Mathematics
2 answers:
Contact [7]3 years ago
7 0

Answer:

X=55

Step-by-step explanation:

Musya8 [376]3 years ago
5 0

Answer:

x+125=180(co-interior angle)

x=180-125=55

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Let me know the answer plz
Gala2k [10]

<u>Answer:</u>

The correct answer option is H. 4374.

<u>Step-by-step explanation:</u>

We are given the following geometric sequence and we are to find its 8th term:

\frac{2}{9}, \frac{2}{3}, 2,...

Here a_1=\frac{2}{9} and common ratio (r) = \frac{\frac{2}{3} }{\frac{2}{9} } =3.

The formula we will use to find the 10th term is:

nth term = a_1 \times r^{(n-1)}

Substituting the values in the formula to get:

10th term = \frac{2}{9} \times 3^{(10-1)}

10th term = 4374

7 0
3 years ago
Which of the following ratlos is not equivalent to 6:10?
Len [333]

Answer:

24/45 or 9/15

Step-by-step explanation:

none of these is equivalent to 6:10

7 0
3 years ago
Select the shape of the graph of y=−2/3x−3 from the selections below.
BARSIC [14]

Step-by-step explanation:

Line through (0,−3) slanting down.

7 0
3 years ago
Please help! Please explain how to do this, I am so lost.
alexdok [17]
Ok, so we know that RST is equal to 6x+12
And RST is also equal to 78 + 3x-12
so we set them equal to each other

6x + 12 = 3x - 12 + 78
And simplify
3x = 54
x = 18

Finally, we solve for the angle with 18 for x

6(18) + 12
108 + 12
120

Hope this helps
8 0
3 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
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