Answer:
B) exothermic.
Explanation:
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In this case, we need to keep in mind that exothermic reactions release heat, so they increase the temperature as the final energy is less than the initial energy; in contrast, endothermic reactions absorb heat, so they decrease the temperature as the final energy is greater than the initial energy.
In such a way, when a dissolution process shows off a negative enthalpy of dissolution, we infer it is an exothermic process due to the aforementioned; therefore, the answer is:
B) exothermic
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Answer:
False
Explanation:
Glucose is a monosachharide carbohydrate, with the molecular formula C₆H₁₂O₆.
Glucose molecule can exist in two forms-
1. Open chain form
2. cyclic form
The open chain form of the glucose is an unbranched 6 carbon atom chain. The carbon 1 of the molecule is an aldehyde group and the rest of the five carbon atoms have one hydroxyl group each.
The cyclic form of the glucose can be-
a. Pyranose: The pyranose form is a 6-membered cyclic ring, which consists of 5 carbon atoms and 1 oxygen atom in the ring.
b. Furanose: The furanose form is a 5- membered cyclic ring, which consists of 4 carbon atoms and 1 oxygen atom in the ring.
In an aqueous solution, 99% glucose molecule exists in the cyclic pyranose form as it is energetically more stable.
Therefore, in aqueous solution, the glucose molecule does not prefer the open-chain conformation.
Therefore, the statement is false.
Answer:
first one
Explanation:
NO ..oxidisation number is +2 and it is reduced to -3 in NH3
H2 oxidisation number is 0 and its oxidized to +1 in H2O
Answer:
Explanation:
H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)
mole of NaOH = 23.6 * 10 ⁻³L * 0.2M
= 0.00472mole
let x be the no of mole of H3PO4 required of 0.00472mole of NaOH
3 mole of NaOH required ------- 1 mole of H3PO4
0.00472mole of NaOH ----------x
cross multiply
3x = 0.0472
x = 0.00157mole
[H3PO4] = mole of H3PO4 / Vol. of H3PO4
= 0.00157mole / (10*10⁻³l)
= 0.157M
<h3>The concentration of unknown phosphoric acid is 0.157M</h3>