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kifflom [539]
3 years ago
7

Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3

O2+ (rapid equilibrium) H3O2+ + Br- ? HOBr + H2O (slow) HOBr+H+ +Br- ?Br2 +H2O(fast) Which rate law is consistent with this mechanism?
a. k[Br-][H+]-1[H2O2]-1
b. k[H+][H2O2][Br-]
c. k[H+][H2O2]
d. k[HOBr][H+][Br-]
Chemistry
1 answer:
Margarita [4]3 years ago
4 0

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}

<u>Step 2:</u>  H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}

<u>Step 3:</u>  HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[H_3O_2^+][Br^-]          ......(1)

As, [H_3O_2^+] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for [H_3O_2^+] from step 1, we get:

K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}  

[H_3O_2^+]=K[H^+][H_2O_2]

Putting the value of [H_3O_2^+] in equation 1, we get:

\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]

Hence, the rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

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50 Points: What is the mass of 6.12 moles of arsenic (As)?
ozzi

The mass of 6.12 moles of arsenic (As) is calculated to be approximately 459g.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles of a substance by its molar mass. That is;

Mass of Arsenic = no. of moles of As × molar mass of As.

According to this question, 6.12 moles of arsenic was given and its molar mass is 74.92g/mol.

Mass of As = 6.12 mol × 74.92g/mol

Mass of As = 459g

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Learn more about mass calculations at: brainly.com/question/8101390

4 0
3 years ago
For a species with a diploid number of 26, indicate how many chromosomes will be present in the somatic nuclei of individuals th
Sedbober [7]

Answer:

Haploid - 13

Triploid - 39

Tetraploid - 52

Trisomic - 27

Monosomic - 25

Explanation:

A haploid organism has half the chromosome number of a diploid version, hence 26/2 = 13

A triploid organism has 3 sets of a haploid chromosomes, hence 13 x 3 = 39

A tetraploid is double of a diploid, 26 x 2 = 52

Trisomic organisms have one extra chromosome in addition to the normal diploid. Hence 26 + 1 = 27

Monosomic organism has one less chromosome than the normal diploid. Hence 26 - 1 = 25

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Calculate the standard entropy change for the following reactions at 25°C.
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Answer:

(a) ΔSº = 216.10 J/K

(b) ΔSº = - 56.4 J/K

(c) ΔSº = 273.8 J/K

Explanation:

We know the standard entropy change for a given reaction is given by the sum of the entropies of the products minus the entropies of reactants.

First we need to find in an appropiate reference table the standard  molar entropies entropies, and then do the calculations.

(a)        C2H5OH(l)          +        3 O2(g)         ⇒        2 CO2(g)     +    3 H2O(g)

Sº            159.9                          205.2                         213.8                  188.8

(J/Kmol)

ΔSº = [ 2(213.8) + 3(188.8) ]   - [ 159.9  + 3(205.) ]  J/K

ΔSº = 216.10 J/K

(b)         CS2(l)               +         3 O2(g)               ⇒      CO2(g)      +      2 SO2(g)

Sº          151.0                              205.2                         213.8                 248.2

(J/Kmol)

ΔSº  = [ 213.8 + 2(248.2) ] - [ 151.0 + 3(205.2) ] J/K = - 56.4 J/K

(c)        2 C6H6(l)           +        15 O2(g)                     12 CO2(g)     +     6 H2O(g)

Sº           173.3                           205.2                           213.8                    188.8

(J/Kmol)  

ΔSº  = [ 12(213.8) + 6(188.8) ] - [ 2(173.3) + 15( 205.2) ] = 273.8 J/K

Whenever possible we should always verify if our answer makes sense. Note that the signs for the entropy change agree with the change in mol gas. For example in reaction (b) we are going from 4  total mol gas reactants to 3, so the entropy change will be negative.

Note we need to multiply the entropies of each substance by  its coefficient in the balanced chemical equation.

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Answer:

Explanation:

A homogenous mixture is a mixture is the same throughout. Some examples are clean water, milk, oil, and food colouring.

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