Answer:
Q = 114349.5 J
Explanation:
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In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:
Thus, the total energy turns out to be:
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Answer:
D
Explanation:
Double Displacement reaction
Both sides are balanced with option D
Answer:
A) 10 moles of CO and 5 moles O2
Answer:
Have similar chemical properties
Explanation:
- The periodic table of elements is made up of groups or families and periods.
- Elements in the same group or chemical family share similar chemical properties.
- For example, elements in group II have similar chemical properties. They include Calcium and magnesium.
- A similar chemical property of group II elements is that they react with water to form metal hydroxide and hydrogen gas.
Answer:
a. The pressure in the flask open to the atmosphere during the vaporization of the unknown liquid is equal to the prevailing atmospheric pressure equivalent to 0.957734 atm
Explanation:
The mass of the empty flask and stopper, m = 53.256 g
The volume of the unknown liquid she adds = 5 mL
The temperature of the water in which she heats up the flask = 98.8 °C = 371.95 K
The mass of the flask and the condensed vapor = 53.780 g
The volume of the flask, V = 231.1 mL
The atmospheric pressure, P = 728 mm Hg
a. We note that the student stoppers the flask after all the liquid has evaporated. Therefore, given that the flask was open to the atmospheric pressure as the liquid evaporates, the pressure of the vapor in the flask is equal to the prevailing atmospheric pressure, or 728 mmHg
Using a calculator, 728 mm Hg is equivalent to 0.957734 atm.
