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2 years ago

Which of these are ways in which a seed might be dispersed? Check all that apply. organisms clouds wind water rocks

Chemistry

2 answers:

alisha [4.7K]2 years ago

6 0

Answer: organisms

wind

water

Explanation:

There are several ways through which plants can move the seed of plants from one place to another. It isn't possible for plants to move their seeds themselves, therefore, there are other methods for their seeds to be moved.

These include fire, wind, animals, organisms, water, fire, water etc. It should be noted that rocks and clouds are not dispersion methods.

I am Lyosha [343]2 years ago

3 0

Answer: Organisms, Wind , Water

Explanation: I got it correct on Edge

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Which of the following is a transuranium element? Ra Am Tc Pa

lyudmila [28]

Am - it has an atomic number of 95 which is greater than 92.

Transuranium elements are elements with atomic levels greater than 92

3 0

2 years ago

Sodium hydrogen carbonate NaHCO3, also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Ac

olga2289 [7]

Answer:

1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of hydrochloric acid = n

Volume of hydrochloric acid solution = 200.0 mL = 0.200 L

Molarity of the hydrochloric acid = 0.089 M

$n=0.089 M\times 0.200 L=0.0178 mol$ of HCL

$HCl(aq)+NaHCO_3(aq)\rightarrow NaCl(aq)+H_2O(l)+CO_2(g)$

According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.

Then 0.0178 moles of HCl wil be neutralized by :

$\frac{1}{1}\times 0.0178 mol=0.0178 mol$ of sodium bicarbonate

Mass of 0.0178 moles of sodium bicarbonate:

0.0178 mol × 72 g/mol = 1.4952 g

1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.

8 0

2 years ago

Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o

sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is 4.50 × 10 ⁻⁴.

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50 × 10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

$[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4} } = 0.0106 M$

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

$\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%$

4 0

3 years ago

On a periodic table, element names are represented by:

alina1380 [7]

Answer: Symbols

Explanation:

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2 years ago

Potassium (k combines with magnesium bromide (mgbr2 to form potassium bromide (kbr and magnesium (mg during a single replacement

Agata [3.3K]

In balancing reactions, the number of atoms on each side should be of equal number. It is the most important rule in reactions. Also, we should know the correct substances involved in the reaction. We do as follows:

2K + MgBr2 = 2KBr + Mg

5 0

3 years ago

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