Answer:
Volume = 746 L
Explanation:
Given that:- Mass of copper(II) fluoride = 175 g
Molar mass of copper(II) fluoride = 101.543 g/mol
The formula for the calculation of moles is shown below:
Thus,
![Moles_{copper(II)\ fluoride}= 1.7234\ mol](https://tex.z-dn.net/?f=Moles_%7Bcopper%28II%29%5C%20fluoride%7D%3D%201.7234%5C%20mol)
Also,
Considering:
So,,
![Volume =\frac{Moles\ of\ solute}{Molarity}](https://tex.z-dn.net/?f=Volume%20%3D%5Cfrac%7BMoles%5C%20of%5C%20solute%7D%7BMolarity%7D)
Given, Molarity = 0.00231 M
So,
![Volume =\frac{1.7234}{0.00231}\ L](https://tex.z-dn.net/?f=Volume%20%3D%5Cfrac%7B1.7234%7D%7B0.00231%7D%5C%20L)
<u>Volume = 746 L</u>
Answer:
D)it creates lower temperatures than nuclear fission reactions
Answer:
When you breathe in, or inhale, your diaphragm contracts and moves downward. This increases the space in your chest cavity, and your lungs expand into it. The muscles between your ribs also help enlarge the chest cavity. They contract to pull your rib cage both upward and outward when you inhale.
Explanation:
^^^
The balanced equation for the reaction is as follows
2RbNO₃ --> 2RbNO₂ + O₂
stoichiometry of RbNO₃ to O₂ is 2:1
number of moles of RbNO₃ decomposed - 5.0 mol
when 2 mol of RbNO₃ decomposes, 1 mol of O₂ is formed
therefore when 5.0 mol of RbNO₃ decomposes - 5.0 / 2 = 2.5 mol of O₂
2.5 mol of O₂ is formed
Reaction of Cu(NO₃)₂ with each salt is as follow,
1) with KNO₃;
Cu(NO₃)₂ + KNO₃ → Cu(NO₃)₂ + KNO₃
Both salt products are water soluble.
2) With CuSO₄;
Cu(NO₃)₂ + CuSO₄ → CuSO₄ + Cu(NO₃)₂
Again both Salt products are water soluble.
3) With K₂SO₄;
Cu(NO₃)₂ + K₂SO₄ → CuSO₄ + 2 KNO₃
Again both salt products are water soluble.
4) With K₂S;
Cu(NO₃)₂ + K₂S → CuS + 2 KNO₃
In this case CuS is water insoluble, hence precipitates out.
Result:
Option-4 is the correct answer.