Answer:
972 ppm
Explanation:
Percent (parts per hundred - pph), parts per million & parts per billion are ratios of a component of interest divided by total mix of several components.
That is, given 28%, this says 28/100, or 28ppm says 28/10⁶, or 28ppb says 28/10⁹.
To convert from the given (=> any of the three concentration ratios) simply multiply (X) where you wish to go.
Examples:
- Convert 35% to ppm and ppb
- 35% = (35/100) x 10⁶ppm = 3.5 x 10⁵ ppm
- _______________________________
- Convert 43 ppm to %
- 43 ppm = (43/10⁶) x 100% = 4.3 x 10³%
- ______________________________
- Convert 81 ppb to ppm
- 81 ppb = (81/10⁹) x 10⁶ppm = 8.1 x 10⁻² ppm
Notice how each 'Given' is expressed as a ratio of amount/100 (given pph or %), or amount/10⁶ (given ppm) or amount/10⁹ (given ppb). All you need to do here is multiply by where you want to go.
=> Given % = (amount/100) x 10⁶ => ppm
=> Given ppm = (amount/10⁶) x 100 => %, or pph
=> Given ppb = (amount/10⁹) x 10⁶ => ppm
Given ratio x 100 = %, or x 10⁶ => ppm or x 10⁹ => ppb
Your Problem:
Given = (0.0972g/100g) x 10⁶ppm = 972 ppm
or, if you wish ppb => (0.0972g/100g) x 10⁹ppb = 972,000 ppb
The activation energy of a reaction is the minimum energy that must be overcome in order for the reaction to take place. One way of reaching the activation energy is by manipulating the process conditions like pressure or temperature. But the most common method is by adding an enzyme. An enzyme speeds up the rate of the reaction but does not actively take part in it.
An analogy would be pushing heavy wooden block down a slope. No matter how many people push on it, the block won't move because of friction. But if you spill oil on the floor, the block would effortlessly move down the slope. The oil here is like an enzyme in a reaction.
333,000 Joules is the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.
Explanation:
Data given:
mass of iron 5 Kg or 5000
initial temperature = 50 degree centigrade
final temperature = 200 degrees centigrade
change in temperature (Δ T= 200 -50 degrees centigrade)
= 150 °C
cp (specific heat capacity of iron) = 0.444j/gram C
q (heat supplied) = ?
applying the formula,
q=mcΔT
putting the values in the equation:
q = 5000 X 0.444 X150
q = 333,000 Joules of energy.
The heat required 333,000 Joules of energy is required.
The balanced chemical reaction would be:
<span>2NI3 = N2 + 3I2
We use the reaction above and the molar masses of the substances involved. We start with the initial amount of NI3 reactant.
3.58 g NI3 (1 mol NI3 / 394.71 g NI3) (3 mol I2 / 2 mol NI3) = 0.0136 mol I2
Therefore, option C is the answer.</span>